没看懂p value

问题如下：

b. What is the p-value of the t-statistic of $\beta$?

解释：

The range of the confidence interval is $2c * se(\widehat\beta)$, where c is the critical value used to construct the 90% confidence interval (5% in each tail, so 1.645). The estimate of $\widehat\beta$ is the midpoint of the confidence interval so 1.105.

Because $\widehat\mu - 1.645se(\widehat\beta) = 0.32$ and $\widehat\mu + 1.645se(\widehat\beta) = 1.89$, these can be solved for $se(\widehat\beta) = .477$. The t-stat is then $\widehat\beta / se(\widehat\beta) = 2.32$.

Finally, the two-sided p-value is2(1 - Φ( |t|)) = 2.06%, where Φ( . ) is the standard normal CDF function. This p-value confirms the rejection in the previous step because it is less than 10%.