开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

Elsa陆艳 · 2022年03月13日

还是没有很懂这个题

NO.PZ2020011303000053

问题如下:

A one-year project has a 3% chance of losing USD 10million, a 7% chance of losing USD 3 million, and a 90% chance of gaining USD 1 million. What are (a) the VaR and (b) the expected shortfall when the confidence level is 95% and the time horizon is one year?

选项:

解释:

VaR is USD 3 million. Expected shortfall (USD) is 10 × 0.6 + 3 × 0.4 = 7.2.

第一问:95%的VAR的损失为什么是3million?不是10milion?

第二步的ES也没有看懂怎么计算的,可以麻烦老师详细讲一下吗?

1 个答案
已采纳答案

李坏_品职助教 · 2022年03月13日

嗨,努力学习的PZer你好:


  1. 这道题var就是找到对应95%的损失。你从最乐观情况的概率开始累加,10milliion对应的损失概率是90% + 3% = 93%,还不够95%的阈值,所以我们需要用最差的那-10 million作为95%的var.
  2. ES是指的损失超过95% var那部分损失的数学期望(均值),由于损失超过95%的概率就是1-95% = 5%,而-10 million的概率只有3%,这个3%在5%里面占了60%,另外的40%只好用-3million损失来填补,所以ES就是10 × 0.6 + 3 × 0.4 = 7.2

----------------------------------------------
虽然现在很辛苦,但努力过的感觉真的很好,加油!

  • 1

    回答
  • 0

    关注
  • 503

    浏览
相关问题

NO.PZ2020011303000053 问题如下 A one-yeprojeha 3% chanof losing US10million, a 7% chanof losing US3 million, ana 90% chanof gaining US1 million. Whare (the Van(the expecteshortfall when the confinlevel is 95% anthe time horizon is one year? Vis US3 million. Expecteshortfall (US is 10 × 0.6 + 3 × 0.4 = 7.2. 有一个项目,3%的概率会损失10m,7%损失3m,90%概率会获得1m,求95%置信区间下的VaR与ES?VaR=3mES=10 × 0.6 + 3 × 0.4 = 7.2m 什么这里的VaR不是用插值法?ES又是按比例算?

2024-09-27 13:21 2 · 回答

NO.PZ2020011303000053 问题如下 A one-yeprojeha 3% chanof losing US10million, a 7% chanof losing US3 million, ana 90% chanof gaining US1 million. Whare (the Van(the expecteshortfall when the confinlevel is 95% anthe time horizon is one year? Vis US3 million. Expecteshortfall (US is 10 × 0.6 + 3 × 0.4 = 7.2. 有一个项目,3%的概率会损失10m,7%损失3m,90%概率会获得1m,求95%置信区间下的VaR与ES?VaR=3mES=10 × 0.6 + 3 × 0.4 = 7.2m 离散型的尾部ES都不能用算数平均,要用这种按比例的算法吗?讲义上有提到吗?

2024-09-27 13:02 2 · 回答

NO.PZ2020011303000053 问题如下 A one-yeprojeha 3% chanof losing US10million, a 7% chanof losing US3 million, ana 90% chanof gaining US1 million. Whare (the Van(the expecteshortfall when the confinlevel is 95% anthe time horizon is one year? Vis US3 million. Expecteshortfall (US is 10 × 0.6 + 3 × 0.4 = 7.2. 有一个项目,3%的概率会损失10m,7%损失3m,90%概率会获得1m,求95%置信区间下的VaR与ES?VaR=3mES=10 × 0.6 + 3 × 0.4 = 7.2m

2024-03-09 17:27 1 · 回答

NO.PZ2020011303000053问题如下A one-yeprojeha 3% chanof losing US10million, a 7% chanof losing US3 million, ana 90% chanof gaining US1 million. Whare (the Van(the expecteshortfall when the confinlevel is 95% anthe time horizon is one year? Vis US3 million. Expecteshortfall (US is 10 × 0.6 + 3 × 0.4 = 7.2. 有一个项目,3%的概率会损失10m,7%损失3m,90%概率会获得1m,求95%置信区间下的VaR与ES?VaR=3mES=10 × 0.6 + 3 × 0.4 = 7.2m 完全不明白,以前的解答不明白,请详细说说,在讲义哪里。谢谢

2023-04-05 17:51 2 · 回答

NO.PZ2020011303000053问题如下A one-yeprojeha 3% chanof losing US10million, a 7% chanof losing US3 million, ana 90% chanof gaining US1 million. Whare (the Van(the expecteshortfall when the confinlevel is 95% anthe time horizon is one year? Vis US3 million. Expecteshortfall (US is 10 × 0.6 + 3 × 0.4 = 7.2. 讲义308页说the ES gives tail losses equweight... 与此处答案的ES计算方法是否冲突?该如何理解?

2022-10-16 19:28 1 · 回答