小王爱学习 · 2022年02月25日
NO.PZ2019052801000031
问题如下：
Today's value of an investment is $89.32, and after 1 years, its future value is $100. What is the continuously compounded rate of return for this investment?
选项：
A.10.52%.
B.11.29%.
C.12.64%.
D.13.72%.
解释：
B is correct.
考点：Interest Rate
解析：
，m=1
所以
老师，我用ln（100/89）和IN100/IN89得出来的结果不一样，为什么会这样，什么情况下应该何在一起，什么情况下应该分开求
NO.PZ2019052801000031问题如下 Toy's value of investment is $89.32, anafter 1 years, its future value is $100. Whis the continuously compounrate of return for this investment? A.10.52%.B.11.29%.C.12.64%.13.72%.B is correct. 考点Interest Rate解析RC=m×ln(1+Rm)R_C=m\times\ln{(1+\frRm)}RC=m×ln(1+mR)R=$100−$89.32$89.32=0.11957R=\frac{\$100-\$89.32}{\$89.32}=0.11957R=$89.32$100−$89.32=0.11957，m=1所以 RC=1×ln(1.11957)=0.1129R_C=1\times\ln{(1.11957)}=0.1129RC=1×ln(1.11957)=0.1129 为什么不能用89.32乘以(1+r)=100
NO.PZ2019052801000031问题如下Toy's value of investment is $89.32, anafter 1 years, its future value is $100. Whis the continuously compounrate of return for this investment? A.10.52%.B.11.29%.C.12.64%.13.72%.B is correct. 考点Interest Rate解析RC=m×ln(1+Rm)R_C=m\times\ln{(1+\frRm)}RC=m×ln(1+mR)R=$100−$89.32$89.32=0.11957R=\frac{\$100-\$89.32}{\$89.32}=0.11957R=$89.32$100−$89.32=0.11957，m=1所以 RC=1×ln(1.11957)=0.1129R_C=1\times\ln{(1.11957)}=0.1129RC=1×ln(1.11957)=0.1129 老师，有两个问题1）请问用n1，pv-89.32，pmt0，fv100这样算iy出来一个近似值行吗。2）公式没看懂
可以直接用ln(100/89.32）吗？
