yh810428 · 2022年01月19日
NO.PZ2015120604000094
问题如下：
Considering Z refers an random varible of the standard normal distribution, P(0≤Z≤1.65) is equal to ?
选项：
A. 0.47.
B. 0.46.
C. 0.45.
解释：
C is correct.
From the standard normal distribution table, F(1.65) = 0.95. So P(0≤Z≤1.65) = F(1.65)-Z(0) = 0.95-0.5 = 0.45.
1.65对应的不是90吗？
NO.PZ2015120604000094 0.46. 0.45. C is correct. From the stanrnormstribution table, F(1.65) = 0.95. So P(0≤Z≤1.65) = F(1.65)-F(0) = 0.95-0.5 = 0.45. 如题。90%减去0左边的0.5，应该得出的是40%？
NO.PZ2015120604000094 老师，请问本题问的是p(z)，记得老师上课讲过p(z）是求密度函数啊，不是累积函数啊，但本题答案是按照F（z）累积函数求面积方法求解的，有点糊涂了哈。
NO.PZ2015120604000094 0.46. 0.45. C is correct. From the stanrnormstribution table, F(1.65) = 0.95. So P(0≤Z≤1.65) = F(1.65)-Z(0) = 0.95-0.5 = 0.45.我记得老师讲的里面1.65是u+1.65✖️标准差。这个是90%，但这道题u没给，标准差也没给，怎么就算出来了呢？谢谢
0.46. 0.45. C is correct. From the stanrnormstribution table, F(1.65) = 0.95. So P(0≤Z≤1.65) = F(1.65)-Z(0) = 0.95-0.5 = 0.45.老师，这个思路错在哪
