开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)｜3.2.5(安卓)APP下载

返回

狂狷 · 2021年11月09日

求单尾假设

  1. CFA I
  2. Quantitative

NO.PZ2018062016000132

问题如下：

Claire believes that the mean price of the commercial residential building is greater than $155,000. The population standard deviation is $25,000. A random sample of 36 commercial residential buildings in the area has a mean price of $159,750. Claire conduct the hypothesis test at a 1% level of significance. The value of the calculated test statistic is closet to:

选项：

A.

1.14.

B.

0.19.

C.

1.33.

解释：

A is correct. This is a one-tailed hypothesis since the alternative hypothesis only allows values greater than the hypothesized value. z=159750-155000/(25000/6)=1.14

求单尾假设significant level是1%还是0.5%
添加评论
1 个答案

星星_品职助教 · 2021年11月09日

同学你好，

1）题干中已经给出了“Claire conduct the hypothesis test at a 1% level of significance”，所以significance level就是1%，不因单尾或是双尾检验而改变；

2）单尾检验意味着拒绝域只在一边，此时这一边的总面积就是1%。

3）无论是拒绝域面积还是significance level，都和本题要求的test statistic无关。求检验统计量不需要考虑significance level。

  • 1

    回答

  • 0

    关注

  • 477

    浏览
相关问题

NO.PZ2018062016000132 问题如下 Claire believes ththe mepriof the commerciresintibuilng is greater th$155,000. The population stanrviation is $25,000. A ranm sample of 36 commerciresintibuilngs in the area ha mepriof $159,750. Claire conthe hypothesis test a 1% level of significance. The value of the calculatetest statistic is closet to: A.1.14. B.0.19. C.1.33. A is correct. This is a one-tailehypothesis sinthe alternative hypothesis only allows values greater ththe hypothesizevalue. z=159750-155000/(25000/6)=1.14 这个25000不是总体样本方差嘛？population不是总体方差嘛？请老师解惑下。

2023-04-27 15:25 1 · 回答

NO.PZ2018062016000132 问题如下 Claire believes ththe mepriof the commerciresintibuilng is greater th$155,000. The population stanrviation is $25,000. A ranm sample of 36 commerciresintibuilngs in the area ha mepriof $159,750. Claire conthe hypothesis test a 1% level of significance. The value of the calculatetest statistic is closet to: A.1.14. B.0.19. C.1.33. A is correct. This is a one-tailehypothesis sinthe alternative hypothesis only allows values greater ththe hypothesizevalue. z=159750-155000/(25000/6)=1.14 这个知识点对应哪一章节

2022-06-29 19:26 1 · 回答

NO.PZ2018062016000132 0.19. 1.33. A is correct. This is a one-tailehypothesis sinthe alternative hypothesis only allows values greater ththe hypothesizevalue. z=159750-155000/(25000/6)=1.1425000/6这步，6是哪个条件出来的？

2022-02-07 13:49 1 · 回答

NO.PZ2018062016000132 我用上方公式算对了这题。但我不明白分子为什么不可以是the hypothesizevalue减去X̄？ 如果是要衡量the hypothesizevalue在分布上离均值X̄多远，既然分布是左右对称，【the hypothesizevalue减去X̄再除以标准误】和【X̄减去the hypothesizevalue再除以标准误】，算出来的数值只是相差了一个正负号。我该怎么理解公式的分子【X̄减去the hypothesizevalue】的意思？

2021-09-15 16:18 1 · 回答