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FrankSun · 2021年10月09日

麻烦解答一下

* 问题详情,请 查看题干

NO.PZ201709270100000502

问题如下:

2. Based on the regression output in Exhibit 1, the first-differenced series used to run Regression 2 is consistent with:

选项:

A.

a random walk.

B.

covariance stationarity.

C.

a random walk with drift.

解释:

B is correct. The critical t-statistic at a 5% confidence level is 1.98. As a result, neither the intercept nor the coefficient on the first lag of the first-differenced exchange rate in Regression 2 differs significantly from zero. Also, the residual autocorrelations do not differ significantly from zero. As a result, Regression 2 can be reduced to yt = εt with a mean-reverting level of b0/(1 b1) = 0/1 = 0.

Therefore, the variance of yt in each period is Var(εt) = σ2. The fact that the residuals are not autocorrelated is consistent with the covariance of the times series, with itself being constant and finite at different lags. Because the variance and the mean of yt are constant and finite in each period, we can also conclude that yt is covariance stationary.

题干描述“neither the intercept nor the coefficient on the first lag of the first-differenced exchange rate in Regression 2 differs significantly from zero”,这句话的意思是方程 yt=b0+b1yt-1+εt的系数假设检验结果为:b0=0,b1=0。

为什么呢?

1 个答案

星星_品职助教 · 2021年10月10日

同学你好,

你列出来的这句话已经说了截距和自变量(the first lag)的系数都不是(neither)“ differs significantly from zero”,即结论为b0=0,b1=0

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