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Sophie · 2021年09月01日

arithmetic return与compounded return的关系

Let’s consider an asset with a 20% standard deviation and a 10% expected arithmetic return. Applying the equation for Rg, this asset has an expected compounded return of 8% (10% – 20%2/2 = 8%)


What happens to the relationship between the arithmetic return and the compounded return when leverage is used?

Answer

Ignoring the cost of funding, if we increase the leverage, there is no additional improvement in return:


Incorporating the cost of funding leverage, the active return is reduced while the volatility remains proportional to the amount of leverage. The Sharpe ratio will decline even faster.

Using the same example, we could show that a portfolio with a leverage of 3× would have the same expected return as an unlevered portfolio if the cost of funding leverage were 2%: (3 × 10% – 2 × 2%) – (3 × 20%)2/2 = 8%


请问:最后加上cost of funding leverage的计算公式,是什么样的?为啥2%的cost是乘以2,麻烦帮讲解一下,谢谢。


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伯恩_品职助教 · 2021年09月01日

嗨,爱思考的PZer你好:


同学你好,你看啊,3倍的杠杆是什么意思,是不是原来值的3倍,也就是比原来多2倍,然后the cost of funding leverage were 2%,也就是说一倍的杠杆是2%,原来的值不花费这2%成本。所以就是3倍的杠杆比原来的值多出来的2倍的值是杠杆,一倍的是2%,两倍的就是2×2%。这样懂了吗?

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