问题如下图:
选项:
A.
B.
C.
解释:
为什么C+=9.4 max(S+ - X,0)
和C+=πu 那个公式得出的结果不一样呢 这里有点儿凌乱
NO.PZ201702190300000305 为什么答案对不上呢? 感谢~!
看到竹子老师画的一个t=2 的图 如果是1 perio= 2 years,折现to C0的时候,分子也要是(1+rf)^ 2 对么
5.12. 7.61. A is correct. Using the expectations approach, the risk-neutrprobability of up move is π= [FV(1) - /(u - = (1.03 - 0.800)/(1.300 - 0.800) = 0.46. The terminvalue calculations for the exercise values Time Step 2 are c++ = Max(0,u2S - X) = Max[0,1.302(38) - 40] = Max(0,24.22) = 24.22. c-+ = Max(0,u - X) = Max[0,1.30(0.80)(38) - 40] = Max(0,-0.48) = 0. - = Max(0,S - X) = Max[0,0.802(38) - 40] = Max(0,-15.68) = 0. scounting bafor two years, the value of the call option Time Step 0 is c = PV[n2c++ + 2n(1 - n)c-+ + (1 - n)2c--]. c = [1/(1.03)]2[0.462(24.22) + 2(0.46)(0.54)(0) + 0.542(0)]. c = [1/(1.03)]2[5.1250] = 4.8308.u 与 pu 与p概念上要怎么理解,常常搞错
老师不是说派u=(1+Rf)T次方*u-,这道题二期二叉树T不是应该等于2吗,为什么派u=(1+Rf)*u-