开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

贺采🌻 · 2021年08月04日

不能用加法法则吗

NO.PZ2018062016000091

问题如下:

Given a discrete random variable Y, the set of all the possible Y value is Y = {20,21,22,23,24,25}.

The estimated value of cumulative distribution function is in the table, what is the probability that Y takes 23 or 25?

选项:

A.

0.50

B.

0.45

C.

0.75

解释:

A is correct. 

F(23) = P(Y≤ 23) = p(20) + p(21) + p(22) + p(23) = 0.55. F(22) = P(Y≤ 22) = p(20) + p(21) + p(22) = 0.30. So p(23) = 0.55-0.30 = 0.25.

For the same reason, F(25) = 1.00, F(24) = 0.75, p(25) = 1.00-0.75 = 0.25.

The probability that Y takes 23 or 25 = p(23) + p(25) = 0.25+0.25 = 0.50

老师,这个取到23或25的概率不可以用加法法则吗(两个至少取到一个的概率) 就是(0.25+0.25)-0.25*0.25
1 个答案
已采纳答案

星星_品职助教 · 2021年08月04日

同学你好,

加法法则的公式为: P(A or B)=P(A)+P(B)-P(AB),而你的列式为P(A or B)=P(A)+P(B)-P(A)×P(B).

--------

这道题用的是加法法则。由于Y取23,和Y取25这两个事件是互斥事件。所以可以得到它们共同发生的概率是0.

所以此时加法法则退化为 P(A or B)=P(A)+P(B),就不存在后面的P(AB)了

  • 1

    回答
  • 0

    关注
  • 359

    浏览
相关问题

NO.PZ2018062016000091 问题如下 Given a screte ranm variable Y, the set of all the possible Y value is Y = {20,21,22,23,24,25}.The estimatevalue of cumulative stribution function is in the table, whis the probability thY takes 23 or 25? A.0.50 B.0.45 C.0.75 A is correct. F(23) = P(Y≤ 23) = p(20) + p(21) + p(22) + p(23) = 0.55. F(22) = P(Y≤ 22) = p(20) + p(21) + p(22) = 0.30. So p(23) = 0.55-0.30 = 0.25. For the same reason, F(25) = 1.00, F(24) = 0.75, p(25) = 1.00-0.75 = 0.25.The probability thY takes 23 or 25 = p(23) + p(25) = 0.25+0.25 = 0.50 还是没看懂题,怎么看是求得是 1-p 而不是三个标准差呢

2022-12-01 14:11 1 · 回答

NO.PZ2018062016000091 问题如下 Given a screte ranm variable Y, the set of all the possible Y value is Y = {20,21,22,23,24,25}.The estimatevalue of cumulative stribution function is in the table, whis the probability thY takes 23 or 25? A.0.50 B.0.45 C.0.75 A is correct. F(23) = P(Y≤ 23) = p(20) + p(21) + p(22) + p(23) = 0.55. F(22) = P(Y≤ 22) = p(20) + p(21) + p(22) = 0.30. So p(23) = 0.55-0.30 = 0.25. For the same reason, F(25) = 1.00, F(24) = 0.75, p(25) = 1.00-0.75 = 0.25.The probability thY takes 23 or 25 = p(23) + p(25) = 0.25+0.25 = 0.50 有点没懂p23和p25怎么算的

2022-08-21 04:11 1 · 回答

NO.PZ2018062016000091 问题如下 Given a screte ranm variable Y, the set of all the possible Y value is Y = {20,21,22,23,24,25}.The estimatevalue of cumulative stribution function is in the table, whis the probability thY takes 23 or 25? A.0.50 B.0.45 C.0.75 A is correct. F(23) = P(Y≤ 23) = p(20) + p(21) + p(22) + p(23) = 0.55. F(22) = P(Y≤ 22) = p(20) + p(21) + p(22) = 0.30. So p(23) = 0.55-0.30 = 0.25. For the same reason, F(25) = 1.00, F(24) = 0.75, p(25) = 1.00-0.75 = 0.25.The probability thY takes 23 or 25 = p(23) + p(25) = 0.25+0.25 = 0.50 本题中为什么P(23)和P(25)属于互斥事件 如何判断互斥事件的情况

2022-07-07 09:41 1 · 回答

NO.PZ2018062016000091 请问,本题的问法是否错误,应该是P(23)anp(25)吧,而不是or

2022-01-27 17:01 1 · 回答