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胡馨梦 · 2021年06月07日

可以算到D5+P5么

NO.PZ2015122802000166

问题如下：

An analyst gathers or estimates the following information about a stock:

Based on a dividend discount model, the stock is most likely:

选项：

A.

undervalued.

B.

fairly valued.

C.

overvalued.

解释：

A is correct.

The current price of €22.56 is less than the intrinsic value (V0) of €24.64; therefore, the stock appears to be currently undervalued. According to the two-stage dividend discount model:

$V_0=\sum_{t=1}^n\frac{{\displaystyle D_0(1+g_s)}^t}{{\displaystyle(1+r)}^t}+\frac{V_n}{{(1+r)}^n}$ and $V_n=\frac{D_{n+1}}{r-g_L}$

D_n₊₁ = D0(1+g_S)ⁿ(1+g_L)

D₁ = €1.60 × 1.09 = €1.744

D₂ = €1.60 × (1.09)² = €1.901

D₃ = €1.60 × (1.09)³ = €2.072

D₄ = €1.60 × (1.09)⁴= €2.259

D₅ = [€1.60 × (1.09)⁴](1.04) = €2.349

V₄ = €2.349/(0.12 – 0.04) = €29.363

$V_0=\frac{1.744}{{(1.12)}^1}+\frac{1.901}{{(1.12)}^2}+\frac{2.072}{{(1.12)}^3}+\frac{2.259}{{(1.12)}^4}+\frac{29.363}{{(1.12)}^4}$

= 1.557+1.515+1.475+1.436+18.661

= €24.64(which is greater than the current price of €22.56)

考点：Multi-stage Model

计算器具体步奏如下：

CFO=0, C01=1.744,F01=1,C02=1.901,F02=1,C03=2.072,F03=1,C04=2.259+29.363,F04=1,NPV , I=12,CPT NPV

可以算到D5➕P5么

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Kiko_品职助教 · 2021年06月08日

嗨，爱思考的PZer你好：

可以的。只不过麻烦了一些。解析中是用D5求的V4，然后计算D1，D2，D3，D4和V4零时刻价值。你也可以算D6求V5，然后把D1，D2，D3，D4，D5和V5折现到零时刻。算出来结果是一样的。

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就算太阳没有迎着我们而来，我们正在朝着它而去，加油！

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NO.PZ2015122802000166 问题如下 analyst gathers or estimates the following information about a stock:Baseon a vinscount mol, the stois most likely: A.unrvalue B.fairly value C.overvalue is correct.The current priof €22.56 is less ththe intrinsic value (V0) of €24.64; therefore, the stoappears to currently unrvalue Accorng to the two-stage vinscount mol:V0=∑t=1n(1+gs)t(1+r)t+Vn(1+r)nV_0=\sum_{t=1}^n\frac{{\splaystyle 0(1+g_s)}^t}{{\splaystyle(1+r)}^t}+\frac{V_n}{{(1+r)}^n}V0=∑t=1n(1+r)t(1+gs)t+(1+r)nVn anVn=+1r−gLV_n=\frac{{n+1}}{r-g_L}Vn=r−gL+1+1 = (1+gS)n(1+gL) = €1.60 × 1.09 = €1.744 = €1.60 × (1.09)2 = €1.901 = €1.60 × (1.09)3 = €2.072 = €1.60 × (1.09)4 = €2.259 = [€1.60 × (1.09)4](1.04) = €2.349V4 = €2.349/(0.12 – 0.04) = €29.363V0=1.744(1.12)1+1.901(1.12)2+2.072(1.12)3+2.259(1.12)4+29.363(1.12)4V_0=\frac{1.744}{{(1.12)}^1}+\frac{1.901}{{(1.12)}^2}+\frac{2.072}{{(1.12)}^3}+\frac{2.259}{{(1.12)}^4}+\frac{29.363}{{(1.12)}^4}V0=(1.12)11.744+(1.12)21.901+(1.12)32.072+(1.12)42.259+(1.12)429.363 = 1.557+1.515+1.475+1.436+18.661 = €24.64(whiis greater ththe current priof €22.56)考点Multi-stage Mol计算器具体步奏如下CFO=0, C01=1.744,F01=1,C02=1.901,F02=1,C03=2.072,F03=1,C04=2.259+29.363,F04=1,NPV , I=12,CPT NPV 此题V4是用什么公式算的？为什么不用讲义P495页求P的公式？求V4,我下方的算法有问题吗？这一类题的解题思路，李老师根本没讲清楚。

2024-08-10 18:02 1 · 回答

NO.PZ2015122802000166 问题如下 analyst gathers or estimates the following information about a stock:Baseon a vinscount mol, the stois most likely: A.unrvalue B.fairly value C.overvalue is correct.The current priof €22.56 is less ththe intrinsic value (V0) of €24.64; therefore, the stoappears to currently unrvalue Accorng to the two-stage vinscount mol:V0=∑t=1n(1+gs)t(1+r)t+Vn(1+r)nV_0=\sum_{t=1}^n\frac{{\splaystyle 0(1+g_s)}^t}{{\splaystyle(1+r)}^t}+\frac{V_n}{{(1+r)}^n}V0=∑t=1n(1+r)t(1+gs)t+(1+r)nVn anVn=+1r−gLV_n=\frac{{n+1}}{r-g_L}Vn=r−gL+1+1 = (1+gS)n(1+gL) = €1.60 × 1.09 = €1.744 = €1.60 × (1.09)2 = €1.901 = €1.60 × (1.09)3 = €2.072 = €1.60 × (1.09)4 = €2.259 = [€1.60 × (1.09)4](1.04) = €2.349V4 = €2.349/(0.12 – 0.04) = €29.363V0=1.744(1.12)1+1.901(1.12)2+2.072(1.12)3+2.259(1.12)4+29.363(1.12)4V_0=\frac{1.744}{{(1.12)}^1}+\frac{1.901}{{(1.12)}^2}+\frac{2.072}{{(1.12)}^3}+\frac{2.259}{{(1.12)}^4}+\frac{29.363}{{(1.12)}^4}V0=(1.12)11.744+(1.12)21.901+(1.12)32.072+(1.12)42.259+(1.12)429.363 = 1.557+1.515+1.475+1.436+18.661 = €24.64(whiis greater ththe current priof €22.56)考点Multi-stage Mol计算器具体步奏如下CFO=0, C01=1.744,F01=1,C02=1.901,F02=1,C03=2.072,F03=1,C04=2.259+29.363,F04=1,NPV , I=12,CPT NPV 请问V4的分母是应该是的数值还是（1+4%）？

2024-01-19 11:42 2 · 回答

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