开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)｜3.2.5(安卓)APP下载

返回

kevinzhu · 2021年02月07日

如何查表

  1. CFA II
  2. Quantitative

* 问题详情，请 查看题干

NO.PZ201512020300000303

问题如下：

3.The most appropriate null hypothesis and the most appropriate conclusion regarding Hansen’s belief about the magnitude of the initial return relative to that of the pre-offer price adjustment (reflected by the coefficient bj) are:

选项：

Null Hypothesis
Conclusion about bj(0.05 Level of Significance)

A.

H0: bj=0.5
Reject H0

B.

H0: bj≥0.5
Fail to reject H0

C.

H0: bj≥0.5
Reject H0

解释：

C is correct.

To test Hansen’s belief about the direction and magnitude of the initial return, the test should be a one-tailed test. The alternative hypothesis is H1: bj<0.5b_j<0.5, and the null hypothesis is H0: bj≥0.5b_j\geq0.5. The correct test statistic is: t = (0.435-0.50)/0.0202 = -3.22, and the critical value of the t-statistic for a one-tailed test at the 0.05 level is -1.645. The test statistic is significant, and the null hypothesis can be rejected at the 0.05 level of significance.

不理解为何这道题目不需要5%/2而是直接选用5%来查表，跟前面的题目如何比较，

添加评论
1 个答案

星星_品职助教 · 2021年02月07日

同学你好，

通过题干的描述分析可得，这道题的备择假设是bj＜0.5。备择假设决定了拒绝域，所以这道题的拒绝域就在左侧，并且是一个单尾检验。

此时0.05 level of significance指的就是左侧拒绝域面积就是0.05或5%。因为这个时候已经不存在右尾了。

根据Exhibit 3，右侧面积为0.050时对应的关键值是1.645，所以根据对称性，左侧面积为0.05时的关键值即为-1.645

-------------------

如果这道题是双尾检验，例如备择假设是Ha：bj≠0，那么此时0.05 level of significance对应的关键值就是1.96了（因为两侧尾部面积总和是5%，单侧就是5%/2=2.5%）

-------------------

这道题是假设检验的问题，假设检验会出现单尾和双尾，取决于备择假设；这点和置信区间问题不同，置信区间（在数量里）一定是有两个尾巴。

  • 1

    回答

  • 1

    关注

  • 500

    浏览
相关问题

NO.PZ201512020300000303 问题如下 3.The most appropriate null hypothesis anthe most appropriate conclusion regarng Hansen’s belief about the magnitu of the initireturn relative to thof the pre-offer priaustment (reflectethe coefficient bj) are: Null HypothesisConclusion about bj(0.05 Level of Significance) A.H0: bj=0.5RejeH0 B.H0: bj≥0.5Fail to rejeH0 C.H0: bj≥0.5RejeH0 C is correct.To test Hansen’s belief about the rection anmagnitu of the initireturn, the test shoula one-tailetest. The alternative hypothesis is H1: 0.5b_j 0.5bj​ 0.5, anthe null hypothesis is H0: bj≥0.5b_j\geq0.5bj​≥0.5. The corretest statistic is: t = (0.435-0.50)/0.0202 = -3.22, anthe criticvalue of the t-statistic for a one-tailetest the 0.05 level is -1.645. The test statistic is significant, anthe null hypothesis crejectethe 0.05 level of significance. 我计算的Sbj=1/(1725^0.5)=0.024077

2024-07-09 11:14 1 · 回答

NO.PZ201512020300000303 问题如下 3.The most appropriate null hypothesis anthe most appropriate conclusion regarng Hansen’s belief about the magnitu of the initireturn relative to thof the pre-offer priaustment (reflectethe coefficient bj) are: Null HypothesisConclusion about bj(0.05 Level of Significance) A.H0: bj=0.5RejeH0 B.H0: bj≥0.5Fail to rejeH0 C.H0: bj≥0.5RejeH0 C is correct.To test Hansen’s belief about the rection anmagnitu of the initireturn, the test shoula one-tailetest. The alternative hypothesis is H1: 0.5b_j 0.5bj​ 0.5, anthe null hypothesis is H0: bj≥0.5b_j\geq0.5bj​≥0.5. The corretest statistic is: t = (0.435-0.50)/0.0202 = -3.22, anthe criticvalue of the t-statistic for a one-tailetest the 0.05 level is -1.645. The test statistic is significant, anthe null hypothesis crejectethe 0.05 level of significance. 请问 这一题计算出来的检验统计量-3.22，为什么不和表里Pre-offer priaustment的检验结果21.53作对比？

2024-01-31 16:01 1 · 回答

NO.PZ201512020300000303 问题如下 3.The most appropriate null hypothesis anthe most appropriate conclusion regarng Hansen’s belief about the magnitu of the initireturn relative to thof the pre-offer priaustment (reflectethe coefficient bj) are: Null HypothesisConclusion about bj(0.05 Level of Significance) A.H0: bj=0.5RejeH0 B.H0: bj≥0.5Fail to rejeH0 C.H0: bj≥0.5RejeH0 C is correct.To test Hansen’s belief about the rection anmagnitu of the initireturn, the test shoula one-tailetest. The alternative hypothesis is H1: 0.5b_j 0.5bj​ 0.5, anthe null hypothesis is H0: bj≥0.5b_j\geq0.5bj​≥0.5. The corretest statistic is: t = (0.435-0.50)/0.0202 = -3.22, anthe criticvalue of the t-statistic for a one-tailetest the 0.05 level is -1.645. The test statistic is significant, anthe null hypothesis crejectethe 0.05 level of significance. 总是把h0和ha的设定有点搞混，不清楚这道题为什么要设定h0为bj大于等于0.5，结论是这样得出来的

2023-04-27 00:12 2 · 回答

NO.PZ201512020300000303 问题如下 3.The most appropriate null hypothesis anthe most appropriate conclusion regarng Hansen’s belief about the magnitu of the initireturn relative to thof the pre-offer priaustment (reflectethe coefficient bj) are: Null HypothesisConclusion about bj(0.05 Level of Significance) A.H0: bj=0.5RejeH0 B.H0: bj≥0.5Fail to rejeH0 C.H0: bj≥0.5RejeH0 C is correct.To test Hansen’s belief about the rection anmagnitu of the initireturn, the test shoula one-tailetest. The alternative hypothesis is H1: 0.5b_j 0.5bj​ 0.5, anthe null hypothesis is H0: bj≥0.5b_j\geq0.5bj​≥0.5. The corretest statistic is: t = (0.435-0.50)/0.0202 = -3.22, anthe criticvalue of the t-statistic for a one-tailetest the 0.05 level is -1.645. The test statistic is significant, anthe null hypothesis crejectethe 0.05 level of significance. criticvalue为什么是负的1.645，而不是1.645？如果是双尾检验，95%的置信区间，criticvalue是否等于1.96？

2023-01-23 21:09 2 · 回答

NO.PZ201512020300000303 老师好 这里T st为啥不是 减去 0.005 虽然题目里说 0.5 percent 也有提到用in cimal. \" corretest statistic is: t = (0.435-0.50)/0.0202 = -3.22\"

2021-11-11 05:26 2 · 回答