Lemonade · 2021年01月20日
问题如下：
Given a stated annual interest rate of 6% compounded quarterly, the level amount that, deposited quarterly, will grow to £25,000 at the end of 10 years is closest to:
选项：
A.£461.
B.£474.
C.£836.
解释：
A is correct.
To solve for an annuity (A) payment, when the future value (FV), interest rate, and number of periods is known, use the following equation:
A=460.68
1、先将6%转化为一年为一期的EAV，（1+6%/4）^4-1=6.1364%
2、再用6.1364%代入计算器中求PMT，N=10,I/Y=6.1364,PV=0,FV=25000，求PMT
可以这样算吗？但是得不到答案，哪里想错了呢？
星星_品职助教 · 2021年01月20日
同学你好，
你列出来的按键中，I/Y是年度利率，N是10年，这样求出来的是年度的PMT。但题干（the level amount that, deposited quarterly）中要求的是季度PMT。
所以这道题将stated annual rate 6%直接转化为季度利率1.5%即可，不用再去求EAR了。同时N转化为40个季度，这样求出来的就是季度的PMT。
计算器按键如下：
I/Y=6/4=1.5；N=10×4=40；PV=0，FV=25,000，CPT PMT=-460.6775，直接选择A选项即可。
𝒜𝒩𝒥𝒜 安雅🎃 · 2021年09月04日
我也是先将stated annual rate转换成EAR，然后按计算器得出一年的PMT是1884.61，再把1884.61➗4，得到471.15。 为什么老师说这题不需要把stated annual rate转成EAR呢?
NO.PZ2017092702000017问题如下Given a stateannuinterest rate of 6% compounquarterly, the level amount that, positequarterly, will grow to £25,000 the enof 10 years is closest to:A.£461.B.£474.C.£836. A is correct. To solve for annuity (payment, when the future value (FV), interest rate, annumber of perio is known, use the following equation:lFV=A[(1+rsm)mN−1rm]25,000=A[(1+0.064)4×10−10.064]{l}FV=A{\lbrack\frac{{(1+\frac{r_s}m)}^{mN}-1}{\frrm}\rbrack}\\25,000=A{\lbrack\frac{{(1+\frac{0.06}4)}^{4\times10}-1}{\frac{0.06}4}\rbrack}lFV=A[mr(1+mrs)mN−1]25,000=A[40.06(1+40.06)4×10−1]A=460.68计算器按法6%/4=1.5%。所以I/Y=1.5，N=10*4=40，FV=25000，PV=0，CPT PMT=-460.6775. 为什么I/Y用的不是EAR/4?
NO.PZ2017092702000017问题如下 Given a stateannuinterest rate of 6% compounquarterly, the level amount that, positequarterly, will grow to £25,000 the enof 10 years is closest to:A.£461.B.£474.C.£836. A is correct. To solve for annuity (payment, when the future value (FV), interest rate, annumber of perio is known, use the following equation:lFV=A[(1+rsm)mN−1rm]25,000=A[(1+0.064)4×10−10.064]{l}FV=A{\lbrack\frac{{(1+\frac{r_s}m)}^{mN}-1}{\frrm}\rbrack}\\25,000=A{\lbrack\frac{{(1+\frac{0.06}4)}^{4\times10}-1}{\frac{0.06}4}\rbrack}lFV=A[mr(1+mrs)mN−1]25,000=A[40.06(1+40.06)4×10−1]A=460.68计算器按法6%/4=1.5%。所以I/Y=1.5，N=10*4=40，FV=25000，PV=0，CPT PMT=-460.6775. 题目从哪里可以看出要求的是PMT
NO.PZ2017092702000017 问题如下 Given a stateannuinterest rate of 6% compounquarterly, the level amount that, positequarterly, will grow to £25,000 the enof 10 years is closest to: A.£461. B.£474. C.£836. A is correct. To solve for annuity (payment, when the future value (FV), interest rate, annumber of perio is known, use the following equation:lFV=A[(1+rsm)mN−1rm]25,000=A[(1+0.064)4×10−10.064]{l}FV=A{\lbrack\frac{{(1+\frac{r_s}m)}^{mN}-1}{\frrm}\rbrack}\\25,000=A{\lbrack\frac{{(1+\frac{0.06}4)}^{4\times10}-1}{\frac{0.06}4}\rbrack}lFV=A[mr(1+mrs)mN−1]25,000=A[40.06(1+40.06)4×10−1]A=460.68计算器按法6%/4=1.5%。所以I/Y=1.5，N=10*4=40，FV=25000，PV=0，CPT PMT=-460.6775. 首先我理解的题目意思是6%年化，1年4次复利，得到EAR，然后在这个EAR水平下也进行每年复利4次，10年后得到25000刀，问每年存入多少钱
NO.PZ2017092702000017 问题如下 Given a stateannuinterest rate of 6% compounquarterly, the level amount that, positequarterly, will grow to £25,000 the enof 10 years is closest to: A.£461. B.£474. C.£836. A is correct. To solve for annuity (payment, when the future value (FV), interest rate, annumber of perio is known, use the following equation:lFV=A[(1+rsm)mN−1rm]25,000=A[(1+0.064)4×10−10.064]{l}FV=A{\lbrack\frac{{(1+\frac{r_s}m)}^{mN}-1}{\frrm}\rbrack}\\25,000=A{\lbrack\frac{{(1+\frac{0.06}4)}^{4\times10}-1}{\frac{0.06}4}\rbrack}lFV=A[mr(1+mrs)mN−1]25,000=A[40.06(1+40.06)4×10−1]A=460.68计算器按法6%/4=1.5%。所以I/Y=1.5，N=10*4=40，FV=25000，PV=0，CPT PMT=-460.6775. 老师，为什么这道题不求EAR呢？为什么我觉得用EAR除以4，才是最终计算器要带入的1/Y呢
NO.PZ2017092702000017 从那句话可以推断出这道题目的PV是0呢？
