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Churning · 2021年01月05日

问一道题:NO.PZ201512020300000606

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问题如下:

Based on Exhibit 1, for the firm with ID #3, Steele should compute the scaled value for the “Interest Expense” variable as:

选项:

A.

0.008

B.

0.083

C.

0.250

解释:

B is correct. Steele uses normalization to scale the financial data. Normalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtracted from each observation
(
Xi), and then this value is divided by the difference between the maximum and minimum values of X (Xmax Xmin) :The firm with ID #3 has an interest expense of 1.2. So, its normalized value is calculated as Xi (normalized) = 0.083



老师问下 这道题不是(1.2-0.4)/(12.2-0.2)=0.8吗 0.833怎么算的呀

1 个答案

星星_品职助教 · 2021年01月05日

同学你好,

Xi(normalized) =(1.2-0.2)/(12.2-0.2)=0.083

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NO.PZ201512020300000606 问题如下 Baseon Exhibit 1, for the firm with I#3, Steele shoulcompute the scalevalue for the “Interest Expense” variable as: A.0.008 B.0.083 C.0.250 B is correct. Steele uses normalization to scale the financitNormalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtractefrom eaobservation(Xi), anthen this value is vithe fferenbetween the maximum anminimum values of X (Xm– Xmin) :The firm with I#3 hinterest expense of 1.2. So, its normalizevalue is calculateXi (normalize =0.083 我的计算理解是将4家公司的利息成本数据进行计算,请老师指正错误分子1.2减0.4;分母1.5减0.4,

2023-12-08 19:33 1 · 回答

NO.PZ201512020300000606 问题如下 Baseon Exhibit 1, for the firm with I#3, Steele shoulcompute the scalevalue for the “Interest Expense” variable as: A.0.008 B.0.083 C.0.250 B is correct. Steele uses normalization to scale the financitNormalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtractefrom eaobservation(Xi), anthen this value is vithe fferenbetween the maximum anminimum values of X (Xm– Xmin) :The firm with I#3 hinterest expense of 1.2. So, its normalizevalue is calculateXi (normalize =0.083 我理解这个公式,不应该是1.1-0.2】/12.2-0.2,不是这样么

2023-05-14 01:10 1 · 回答

NO.PZ201512020300000606 老师,这里也可以算stanrzation,1.2-0.2/4,为什么要用normailization?

2021-04-25 19:56 1 · 回答

NO.PZ201512020300000606 老师,怎么就通过此题问题联系到normalization?

2021-02-17 11:39 1 · 回答