问题如下:
We want to use z-statistic to construct confidence interval for a normally distribution. Assume the sample size is 100, sample mean is 15% and the standard deviation of sample is 25%. The significance level is supposed to be 10% , the confidence interval is :
选项:
A. - 10.88% to 19.13%.
B. 10.88% to 19.13%.
C. 10.88% to 20.57%.
解释:
B is correct.
In this case, we can know that the Confidence Interval=[Point Estimate +/- (reliability factor)*Standard error]=
请问我理解10%不是应该对应双尾,也就是中间部分应该是80%,这么理解有哪里不对吗?