问题如下:
Peter collectes the following information from a company Y:
Based on the information provided, the price/earnings multiple for the company Y is closest to:
选项:
A. 7.5
B. 8.3
C. 4.9
解释:
B is correct.
老师,这道题用的是leading pe计算,是因为给的数据都是预期的吗
NO.PZ2018062002000176问题如下 Peter collectes the following information from a company Y:Baseon the information provi the price/earnings multiple for the company Y is closest to:A.7.5B.8.3C.4.9 B is correct.P0E1=E1r−g=\frac{{\text{P}}_\text{0}}{{\text{E}}_1}=\frac{\frac{1}{E_1}}{r-g}=\frac{}{}E1P0=r−gE1=3/6(8%−2%)=8.33/6(8\%-2\%)=8.33/6(8%−2%)=8.3考点PriMultiple Approach这道题解析的计算过程已经很详细了,不再赘述。 如果用公式P0=(1+g)/r-g这个公式算出P0为什么不可以呢
NO.PZ2018062002000176 问题如下 Peter collectes the following information from a company Y:Baseon the information provi the price/earnings multiple for the company Y is closest to: A.7.5 B.8.3 C.4.9 B is correct.P0E1=E1r−g=\frac{{\text{P}}_\text{0}}{{\text{E}}_1}=\frac{\frac{1}{E_1}}{r-g}=\frac{}{}E1P0=r−gE1=3/6(8%−2%)=8.33/6(8\%-2\%)=8.33/6(8%−2%)=8.3考点PriMultiple Approach这道题解析的计算过程已经很详细了,不再赘述。 3/6(8%-2%)=8.3請問3/6,在這代表甚麽?
NO.PZ2018062002000176问题如下Peter collectes the following information from a company Y:Baseon the information provi the price/earnings multiple for the company Y is closest to: A.7.5 B.8.3 C.4.9 B is correct.P0E1=E1r−g=\frac{{\text{P}}_\text{0}}{{\text{E}}_1}=\frac{\frac{1}{E_1}}{r-g}=\frac{}{}E1P0=r−gE1=3/6(8%−2%)=8.33/6(8\%-2\%)=8.33/6(8%−2%)=8.3考点PriMultiple Approach这道题解析的计算过程已经很详细了,不再赘述。 这题什么不多乘1+g,或者出现什么特征的题显示出来是直接用p
为什么不能这么算 P/E1=(1-b)/{(r-g)*E1}=(1-0.5)/(6*6%) b=0.5=(6-3)/3 RR=预期earning-预期vind