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尼克内姆 · 2020年06月25日

问一道题:NO.PZ2015120604000145 [ CFA I ]

问题如下:

Here is a table discribing sample statistics from two bonds' rate of return which are both normally distributed over the past decades. If an investor is considering whether the mean of bond A is equal to 22%,

which of the following conclusion is least appropriate (significant level=1%) ?

选项:

A.

The null hypothesis can be rejected.

B.

It is appropriate to use a two-tailed t-test.

C.

The test statistic value is 1.333.

解释:

A is correct.

The null hypothesis:  H0: μ=22%.

Because the sample size is 25, which is less than 30, so it is appropriate to use the two-tailed t-test.

t24=x-μ0sn=0.26-0.220.1525=1.333

±t24 at α= 0.01= ±2.797;

Because -2.797 <1.333<+2.797, therefore, H0 cannot be rejected.

confidence interval=26%+T(24) 0.5*(15%/3) 请问我这个计算错在哪里???

1 个答案

星星_品职助教 · 2020年06月29日

同学你好,

1. 这道题并没有必要计算置信区间,用置信区间判断和用关键值判断的结果虽然一致,但是麻烦的多,也不是上课讲的重点

2. 置信区间的公式为26%±T(24) ×(15%/5) ,可以对照讲义上的公式,首先公式里的α/2并不代表真除以2,而是单侧尾部面积的意思,其次对于均值的标准差(标准误),分母除以的是根号n,也就是根号25,结果为5,而不是3.

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