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momo1997 · 2017年11月14日

问一道题:NO.PZ2017092702000030 [ CFA I ]怎么按计算器呢?

问题如下图:
选项:
A.
B.
C.
解释:
1 个答案

源_品职助教 · 2017年11月14日

这题不好直接调用计算器CF功能求解。

你可以先把每一期投资的净现金流算出来,然后再如如计算器

那么CF0=10CF1=100CF2=-(10*1.14*1.08+100*1.08)

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NO.PZ2017092702000030问题如下the beginning of Ye1, a funh$10 million unr management; it earns a return of 14% for the year. The funattracts another $100 million the start of Ye2 anearns a return of 8% for thyear. The money-weighterate of return is most likely:A.less ththe time-weighterate of return. B.the same the time-weighterate of return. C.greater ththe time-weighterate of return.A is correct. The money-weighterate of return is founsetting the present value (PV) of investments into the funequto the PV of the funs terminvalue. Because most of the investment came ring Ye2, the measure will biasetowarthe performanof Ye2. Set the PV of investments equto the PV of the funs terminvalue: 10+1001+r=10×1.14×1.08+100×1.08(1+r)210+\frac{100}{1+r}=\frac{10\times1.14\times1.08+100\times1.08}{{(1+r)}^2}10+1+r100​=(1+r)210×1.14×1.08+100×1.08​ Solving for r results in r = 8.53%. The time-weightereturn of the funis =(1.14)(1.08)2−1=10.96\sqrt[2]{{(1.14)}{(1.08)}}-1=10.962(1.14)(1.08)​−1=10.96CF0 -10CF1 1.4-100CF2 100*0.08+10*0.08

2023-11-11 19:27 2 · 回答

NO.PZ2017092702000030 问题如下 the beginning of Ye1, a funh$10 million unr management; it earns a return of 14% for the year. The funattracts another $100 million the start of Ye2 anearns a return of 8% for thyear. The money-weighterate of return is most likely: A.less ththe time-weighterate of return. B.the same the time-weighterate of return. C.greater ththe time-weighterate of return. A is correct. The money-weighterate of return is founsetting the present value (PV) of investments into the funequto the PV of the funs terminvalue. Because most of the investment came ring Ye2, the measure will biasetowarthe performanof Ye2. Set the PV of investments equto the PV of the funs terminvalue: 10+1001+r=10×1.14×1.08+100×1.08(1+r)210+\frac{100}{1+r}=\frac{10\times1.14\times1.08+100\times1.08}{{(1+r)}^2}10+1+r100​=(1+r)210×1.14×1.08+100×1.08​ Solving for r results in r = 8.53%. The time-weightereturn of the funis =(1.14)(1.08)2−1=10.96\sqrt[2]{{(1.14)}{(1.08)}}-1=10.962(1.14)(1.08)​−1=10.96

2023-09-06 00:23 1 · 回答

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2023-02-27 15:49 3 · 回答

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2022-11-20 20:37 1 · 回答

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2022-10-29 22:19 1 · 回答