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十六岁的烟火 · 2020年05月22日

问一道题:NO.PZ2016082406000005 [ FRM II ]

问题如下:

Define unexpected loss (UL) as the standard deviation of losses and expected loss (EL) as the average loss. Further define LGD as loss given default, and EDF as the expected default frequency. Which of the following statements hold(s) true?

I.     EL increases linearly with increasing EDF.

II.   EL is often higher than UL.

III. With increasing EDF, UL increases at a much faster rate than EL.

IV. The lower the LGD, the higher the percentage loss for both the EL and UL.

选项:

A.

I only

B.

I and II

C.

I and III

D.

II and IV

解释:

ANSWER: C

Equation:E(CL)=E(n)E(LGD)=NpE(LGD)E{(CL)}=E{(n)}E{(LGD)}=NpE{(LGD)}shows that EL increases linearly with p, so answer I. is correct. Answer II. is not correct, certainly for concentrated portfolios. Equation: σ(CL)=p×σ2(LGD)+p×(1p)×[E(LGD)]2\sigma{(CL)}=\sqrt{p\times\sigma^2{(LGD)}+p\times{(1-p)}\times{\lbrack E{(LGD)}\rbrack}^2}shows that UL increases faster than EL linearly with p, so answer III. is correct. Finally, Answer II. is incorrect, as higher (not lower) LGD would lead to higher credit losses.

老师,这个EDF指的是什么?
2 个答案
已采纳答案

袁园_品职助教 · 2020年05月25日

是的,是PD

袁园_品职助教 · 2020年05月23日

同学你好!

题目中有说: EDF as the expected default frequency

十六岁的烟火 · 2020年05月24日

就是PD吗

十六岁的烟火 · 2020年05月24日

或者说,是EL和UL公式里的哪个参数?

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fine unexpecteloss (UL) the stanrviation of losses anexpecteloss (EL) the average loss. Further fine LGloss given fault, anE the expectefault frequency. Whiof the following statements hols) true? I.     EL increases linearly with increasing E. II.   EL is often higher thUL. III. With increasing E, UL increases a mufaster rate thEL. IV. The lower the LG the higher the percentage loss for both the EL anUL. I only I anII I anIII II anIV ANSWER: C Equation: E(CL)=E(n)E(LG=NpE(LGE{(CL)}=E{(n)}E{(LG}=NpE{(LG}E(CL)=E(n)E(LG=NpE(LGshows thEL increases linearly with p, so answer I. is correct. Answer II. is not correct, certainly for concentrateportfolios. Equation: σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2\sigma{(CL)}=\sqrt{p\times\sigma^2{(LG}+p\times{(1-p)}\times{\lbraE{(LG}\rbrack}^2}σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2 ​shows thUL increases faster thEL linearly with p, so answer III. is correct. Finally, Answer II. is incorrect, higher (not lower) LGwoulleto higher cret losses. 你好请问III应该怎么理解,为什么一单位P上升UL比EL提升多

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