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sarahjia · 2020年03月06日

问一道题：NO.PZ2015120604000147

  1. CFA I
  2. Quantitative

问题如下：

Here is a table discribing sample statistics from two bonds' rate of return which are both normally distributed over the past decades. If an investor is considering whether the mean of bond B is greater than 26%,

which of the following conclusion is least appropriate (significant level=5%) ?

选项：

A.

It is approptiate to use the Z-test.

B.

The mean of bond B is not significant greater than 26%.

C.

It is a one-tailed test.

解释：

B is correct.

It is appropraite to ues the one-tailed Z-test because the sample size of bond B is bigger than 30.

The null hypothesis is: H0: μ ≤ 26%

The test statistic:Z=X-μSxn =(0.32-0.26)0.2249=1.91

 α= 5% indicates the critical value is equal to ±1.65.

Because 1.91>1.65, therefore, we should reject the null hypothesis.

老师你好，这道题我用的排除法因为normal distribution所以可以用Z，然后就是题干中说greater than 26%，那么就是单尾所以选B，不知道我这个理解的思路和做这道题的思路对不对呢，还是要进行计算来得出这道题的答案，谢谢

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星星_品职助教 · 2020年03月06日

同学你好，

这个排除的思路可以用于解这道题。

但B选项的计算也要掌握一下，不排除别的题目无法用排除法而需要计算的。用Z检验统计量计算的公式，（32%-26%）/（22%/√49）=1.91，然后再跟临界值1.65比较，发现要拒绝原假设，所以应该是significant，就可以了。

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