开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

SkipperLin · 2020年02月08日

问一道题:NO.PZ2020010303000009

问题如下:

Either using a Z table or the Excel function NORM.S.DIST, compute

a. Pr(-1.5 < Z < 0), where Z ∼ N(0, 1)

b. Pr(Z < -1.5), where Z ∼ N(0, 1)

c. Pr(-1.5 < X < 0), where X ∼ N(1, 2)

d. Pr(X > 2), where X ∼ N(1, 2)

e. Pr(W > 12), where W ∼ N(3, 9)

选项:

解释:

a. 43.3%. In Excel, the command to compute this value is NORM.S.DIST(0,TRUE) – NORM.S.DIST(-1.5,TRUE).

b. 6.7%. In Excel, the command to compute this value is NORM.S.DIST(-1.5,TRUE).

c. 20.1%. In Excel, the command to compute this value is NORM.S.DIST((0 – 1)/SQRT(2),TRUE) – NORM.S.DIST((-1.5-1)>SQRT(2),TRUE).

d. 24.0%. In Excel, the command to compute this value is 1 – NORM.S.DIST((2 – 1)/SQRT(2),TRUE).

e. 0.13%. In Excel, the command to compute this value is 1 – NORM.S.DIST((12 – 3)/3,TRUE).

请问第三题这种应该怎么转换

1 个答案

品职答疑小助手雍 · 2020年02月08日

同学你好,第三问的分布是服从(1,2)的正态分布,所以0 到均值1的距离就是(0-1)/根号2 倍的标准差(后面公式的前半部分就是求负无穷到这个点的累计概率),-1.5到均值1的距离就是(-1.5-1)/根号2 倍的标准差(后面公式的后半部分就是求负无穷到这个点的累计概率)。

负无穷到0的累计概率减去负无穷到-1.5的累计概率,就是得到他俩之间的累计概率了。

SkipperLin · 2020年02月09日

了解 请问如果是查表的话 是不是先看表算出Pr(-1.5 < X < 0)在标准正态分布的概率 然后假设这个概率是x,得到x之后我们在x*sqrt(2) + 1也可以?

品职答疑小助手雍 · 2020年02月09日

不行,不能用概率*根号2这样。这期间的概率分布不是对于标准正态和(1,2)的正态不是等比例的。

  • 1

    回答
  • 0

    关注
  • 385

    浏览
相关问题

NO.PZ2020010303000009问题如下Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). -1·5 Z 0如何查表得出的结果

2024-04-16 13:08 1 · 回答

NO.PZ2020010303000009 问题如下 Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). excel function NORM.S.ST 这是Excel的计算公式吗?这个也需要掌握吗

2024-01-15 00:04 1 · 回答

NO.PZ2020010303000009 问题如下 Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). 这道题除了有超出给定表的数据,还有无法精准得出的,比如1.5,在表单中只有接近1.5的数据,这种情况怎么计算?

2024-01-14 23:32 2 · 回答

NO.PZ2020010303000009 问题如下 Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). 是不是可以标准化到 P(-1.77 X -0.71)这个式子,在去查表但是-1.77超过了将以中给的表的范围

2023-02-26 15:41 1 · 回答

NO.PZ2020010303000009 问题如下 Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). 具体怎么做呢?请问能用算式一下吗

2023-01-31 10:24 2 · 回答