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🌊 梅根 · 2020年02月03日

问一道题:NO.PZ2020010301000005 [ FRM I ]

问题如下:

Based on the probabilities in the plot below, what are the values of the following?

a. Pr(AC)Pr(A^C)

b. Pr(D|A∪B∪C)

c. Pr(A|A)

d. Pr(B|A)

e. Pr(C|A)

f. Pr(D|A)

g. Pr((AD)C)Pr({(A∪D)}^C)

h. Pr((ACDC))Pr((A^C\bigcap D^C))

i. Are any of the four events pairwise independent?

解释:

a. 1 - Pr(A) = 100% - 30% = 70%

b. This value is Pr(D∩(A∪B∪C))/Pr(A∪B∪C). The total probability in the three areas A, B, and C is 73%. The overlap of D with these three is 9% + 8% + 7% = 24%, and so the conditional probability is 24%/73%= 33%.

c. This is trivially 100%.

d. Pr(B∩A) = 9%. The conditional probability is 9%/30% = 30%.

e. There is no overlap and so Pr(C∩A) = 0.

f. Pr(D∩A) = 9%. The conditional probability is 30%.

g. This is the total probability not in A or D. It is 1 – Pr(A∪D) = 1 - (Pr(A) + Pr(D) - Pr(A∩D)) = 100% - (30% + 36% - 9%) = 43%.

h. This area is the intersection of the space not in A with the space not in D. This area is the same as the area that is not in A or D, Pr((A∪D)C) and so 43%.

i. The four regions have probabilities A = 30%, B = 30%, C = 28% and D = 36%. The only region that satisfied the requirement that the joint probability is the product of the individual probabilities is A and B because Pr(A∩B) = 9% = Pr(A)Pr(B) = 30% * 30%.

第h题,我套用公式计算为什么不对呢?以下是我的思路。P((Ac∩Dc))=(1-P(A))×(1-P(B))=70%×68%=44.8%

1 个答案

品职答疑小助手雍 · 2020年02月07日

同学你好,首先要掌握答案里那个性质,即(非A)交(非D)等同于非(A并D)。你这样算是认为非A和非D是相互独立的了,但其实不独立。


这题感觉在脑海里想象一下把目标区域涂黑结果容易出来一些。

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