开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

Stacie · 2020年01月19日

问一道题:NO.PZ2020010303000009 [ FRM I ]

问题如下图:

请问这道题在计算器上应该怎么按啊?我看解题结果是用excel的

1 个答案
已采纳答案

orange品职答疑助手 · 2020年01月19日

同学你好,不需要掌握用计算器计算累计正态分布,只要能转换成标准正态分布的计算式,比如a中Z>-1.5转换成 1-N(-1.5)即可。题目会给你很多正态分布的值让你选的,只要从中选出N(-1.5)即可。

  • 1

    回答
  • 0

    关注
  • 403

    浏览
相关问题

NO.PZ2020010303000009问题如下Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). -1·5 Z 0如何查表得出的结果

2024-04-16 13:08 1 · 回答

NO.PZ2020010303000009 问题如下 Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). excel function NORM.S.ST 这是Excel的计算公式吗?这个也需要掌握吗

2024-01-15 00:04 1 · 回答

NO.PZ2020010303000009 问题如下 Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). 这道题除了有超出给定表的数据,还有无法精准得出的,比如1.5,在表单中只有接近1.5的数据,这种情况怎么计算?

2024-01-14 23:32 2 · 回答

NO.PZ2020010303000009 问题如下 Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). 是不是可以标准化到 P(-1.77 X -0.71)这个式子,在去查表但是-1.77超过了将以中给的表的范围

2023-02-26 15:41 1 · 回答

NO.PZ2020010303000009 问题如下 Either using a Z table or the Excel function NORM.S.ST, compute Pr(-1.5 Z 0), where Z ∼ N(0, 1) Pr(Z -1.5), where Z ∼ N(0, 1) Pr(-1.5 X 0), where X ∼ N(1, 2) Pr(X 2), where X ∼ N(1, 2) e. Pr(W 12), where W ∼ N(3, 9) 43.3%. In Excel, the commanto compute this value is NORM.S.ST(0,TRUE) – NORM.S.ST(-1.5,TRUE).6.7%. In Excel, the commanto compute this value is NORM.S.ST(-1.5,TRUE).20.1%. In Excel, the commanto compute this value is NORM.S.ST((0 – 1)/SQRT(2),TRUE) – NORM.S.ST((-1.5-1)/SQRT(2),TRUE). 24.0%. In Excel, the commanto compute this value is 1 – NORM.S.ST((2 – 1)/SQRT(2),TRUE).e. 0.13%. In Excel, the commanto compute this value is 1 – NORM.S.ST((12 – 3)/3,TRUE). 具体怎么做呢?请问能用算式一下吗

2023-01-31 10:24 2 · 回答