问一道题：NO.PZ2019070101000037 [ FRM I ]

NO.PZ2019070101000037 问题如下 Baseon the table, the value of a 1.5-year, 6% semiannucoupon, $100 pvalue bonis closest to: A.$102.19. B.$103.42. C.$104.00. $105.66. C is correct考点BonPrice解析请根据图表信息求出期限1.5年，半年付息一次，coupon rate为6%，面值为100的债券价格。债券价格等于债券未来现金流的折现求和，每一笔coupon的折现率应使用对应期限的spot rate。Bonpri= 31+0.02502+3(1+0.03002)2+103(1+0.03262)3=104.00\frac{3}{1+\frac{0.0250}{2}}+\frac{3}{(1+{\frac{0.0300}{2}})^2}+\frac{103}{(1+\frac{0.0326}{2})^3}=104.001+20.0250​3​+(1+20.0300​)23​+(1+20.0326​)3103​=104.00 $3 (1+ 0.0250 2 ) 1 + $3 (1+ 0.0300 2 ) 2 + $103 (1+ 0.0326 2 ) 3 =$104.00 讲义上一道类似的题何老师给出了三种方法，折现因子、spot rate和forwarrate来做。请问这道题可以用折现因子解答吗

NO.PZ2019070101000037问题如下 Baseon the table, the value of a 1.5-year, 6% semiannucoupon, $100 pvalue bonis closest to: A.$102.19.B.$103.42.C.$104.00.$105.66. C is correct考点BonPrice解析请根据图表信息求出期限1.5年，半年付息一次，coupon rate为6%，面值为100的债券价格。债券价格等于债券未来现金流的折现求和，每一笔coupon的折现率应使用对应期限的spot rate。Bonpri= 31+0.02502+3(1+0.03002)2+103(1+0.03262)3=104.00\frac{3}{1+\frac{0.0250}{2}}+\frac{3}{(1+{\frac{0.0300}{2}})^2}+\frac{103}{(1+\frac{0.0326}{2})^3}=104.001+20.0250​3​+(1+20.0300​)23​+(1+20.0326​)3103​=104.00 $3 (1+ 0.0250 2 ) 1 + $3 (1+ 0.0300 2 ) 2 + $103 (1+ 0.0326 2 ) 3 =$104.00 第三期可以直接用95.2652吗？

NO.PZ2019070101000037 $103.42. $104.00. $105.66. C is corre考点BonPri解析Bonpri= 31+0.02502+3(1+0.03002)2+103(1+0.03262)3=104.00\frac{3}{1+\frac{0.0250}{2}}+\frac{3}{(1+{\frac{0.0300}{2}})^2}+\frac{103}{(1+\frac{0.0326}{2})^3}=104.001+20.0250​3​+(1+20.0300​)23​+(1+20.0326​)3103​=104.00 $3 (1+ 0.0250 2 ) 1 + $3 (1+ 0.0300 2 ) 2 + $103 (1+ 0.0326 2 ) 3 =$104.00 复利这样算对吗……如图