问题如下图：
选项：
A. 
B. 
C. 
解释：
老师 这个统计量怎么表示 我看讲义上没有
星星_品职助教 · 2019年10月15日
同学你好，这个统计量很复杂。考纲对这部分的要求仅是“identify”，如果有兴趣可以看一下20年原版书R12， 3.2 Tests Concerning Differences between Means，相关计算在Equation 7.
你最近看的这部分是各种假设检验的总结，这部分对于考试的要求重点是讲义上总结的各个类型的假设检验的那个表格。涉及计算的重点还是集中于之前的单个均值如何检验，和今年考纲新增的correlation检验，其余的了解什么情况下做什么检验即可。加油
PaisleyPPx · 2019年10月16日
老师 这道题的判断标准（拒绝域）是跟Z分布一样吗？
星星_品职助教 · 2019年10月16日
字数比较多，新起了个回复回了哈
NO.PZ2018062016000140问题如下ring the table below, the memonthly return of X Inx in the first five years have been fferent ththe mereturn in the seconfive years.Let the μ1 stanfor the population mereturn for the year1 through ye5 anμ2 stanfor the population mereturn for the ye6 through ye10, the following hypothese: H0: μ1 – μ2 = 0 versus Hμ1 – μ2 ≠ 0 Assume ththe significant level is 0.05Whiof the following options is most accurate?A.The null hypothesis will rejecteif t -1.98 or t 1.98. B.The t-test h119 grees of freem. C.The rejection points are ±1.658.A is correct. The two samples are awn from two fferent time perio, so they are inpennt samples. The population variances cassumeto equal. Unr all consirations, the t-test h60+60-2=118 grees of freem.For a two-tailetest, the significant level of 0.05, the rejection points are ±1.980, so we will rejethe null if t -1.980 or t 1.980.谢谢谢。。。。。。。
NO.PZ2018062016000140 问题如下 ring the table below, the memonthly return of X Inx in the first five years have been fferent ththe mereturn in the seconfive years.Let the μ1 stanfor the population mereturn for the year1 through ye5 anμ2 stanfor the population mereturn for the ye6 through ye10, the following hypothese: H0: μ1 – μ2 = 0 versus Hμ1 – μ2 ≠ 0 Assume ththe significant level is 0.05Whiof the following options is most accurate? A.The null hypothesis will rejecteif t -1.98 or t 1.98. B.The t-test h119 grees of freem. C.The rejection points are ±1.658. A is correct. The two samples are awn from two fferent time perio, so they are inpennt samples. The population variances cassumeto equal. Unr all consirations, the t-test h60+60-2=118 grees of freem.For a two-tailetest, the significant level of 0.05, the rejection points are ±1.980, so we will rejethe null if t -1.980 or t 1.980. 为什么是t分布呢
NO.PZ2018062016000140 问题如下 ring the table below, the memonthly return of X Inx in the first five years have been fferent ththe mereturn in the seconfive years.Let the μ1 stanfor the population mereturn for the year1 through ye5 anμ2 stanfor the population mereturn for the ye6 through ye10, the following hypothese: H0: μ1 – μ2 = 0 versus Hμ1 – μ2 ≠ 0 Assume ththe significant level is 0.05Whiof the following options is most accurate? A.The null hypothesis will rejecteif t -1.98 or t 1.98. B.The t-test h119 grees of freem. C.The rejection points are ±1.658. A is correct. The two samples are awn from two fferent time perio, so they are inpennt samples. The population variances cassumeto equal. Unr all consirations, the t-test h60+60-2=118 grees of freem.For a two-tailetest, the significant level of 0.05, the rejection points are ±1.980, so we will rejethe null if t -1.980 or t 1.980. 由于拒绝原假设的原则为|t-statistic|＞|criticvalue|，可知A正确。請問|t-statistic|為多少？這題如何計算，謝謝，
NO.PZ2018062016000140问题如下ring the table below, the memonthly return of X Inx in the first five years have been fferent ththe mereturn in the seconfive years.Let the μ1 stanfor the population mereturn for the year1 through ye5 anμ2 stanfor the population mereturn for the ye6 through ye10, the following hypothese: H0: μ1 – μ2 = 0 versus Hμ1 – μ2 ≠ 0 Assume ththe significant level is 0.05Whiof the following options is most accurate?A.The null hypothesis will rejecteif t -1.98 or t 1.98. B.The t-test h119 grees of freem. C.The rejection points are ±1.658.A is correct. The two samples are awn from two fferent time perio, so they are inpennt samples. The population variances cassumeto equal. Unr all consirations, the t-test h60+60-2=118 grees of freem.For a two-tailetest, the significant level of 0.05, the rejection points are ±1.980, so we will rejethe null if t -1.980 or t 1.980.可以詳細講一下做題思路嗎
NO.PZ2018062016000140 The t-test h119 grees of freem. The rejection points are ±1.658. A is correct. The two samples are awn from two fferent time perio, so they are inpennt samples. The population variances cassumeto equal. Unr all consirations, the t-test h60+60-2=118 grees of freem.For a two-tailetest, the significant level of 0.05, the rejection points are ±1.980, so we will rejethe null if t1.980. 为什么是T分布不是Z分布呢 从题干哪里可以判断哇