问一道题：NO.PZ2019052801000034 [ FRM I ]

NO.PZ2019052801000034 问题如下 Assume ththe annucontinuously compounspot rates are: Z1=5%,Z_1=5\%,Z1​=5%, Z2=5.1%,Z_2=5.1\%,Z2​=5.1%, Z3=5.2%,Z_3=5.2\%,Z3​=5.2%,The 1.5-ye bonha $100 favalue, 6% semiannucoupon payment. Calculate the bonprice: A.$98.34. B.$99.73. C.$100.52. $101.05. is correct. 考点Interest Rate解析lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05{l}B=3\times e^{\lbrack{(-0.05/2)}\times1\rbrack}+3\times e^{\lbrack{(-0.051/2)}\times2\rbrack}+103\times e^{\lbrack{(-0.052/2)}\times3\rbrack}\\=2.93+2.85+95.27=\$101.05lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05 老师，这里的次方里面为什么还要乘以1,2,3？

NO.PZ2019052801000034问题如下Assume ththe annucontinuously compounspot rates are: Z1=5%,Z_1=5\%,Z1​=5%, Z2=5.1%,Z_2=5.1\%,Z2​=5.1%, Z3=5.2%,Z_3=5.2\%,Z3​=5.2%,The 1.5-ye bonha $100 favalue, 6% semiannucoupon payment. Calculate the bonprice: A.$98.34.B.$99.73.C.$100.52.$101.05.is correct. 考点Interest Rate解析lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05{l}B=3\times e^{\lbrack{(-0.05/2)}\times1\rbrack}+3\times e^{\lbrack{(-0.051/2)}\times2\rbrack}+103\times e^{\lbrack{(-0.052/2)}\times3\rbrack}\\=2.93+2.85+95.27=\$101.05lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05 老师您好，之前课程里讲过，yielrate是0息债利率的平均数，那我可以先（Z1+Z2+Z3）/3求出yielrate，然后用连续复利的方式求吗？但我按计算器是42？差好多

NO.PZ2019052801000034 问题如下 Assume ththe annucontinuously compounspot rates are: Z1=5%,Z_1=5\%,Z1​=5%, Z2=5.1%,Z_2=5.1\%,Z2​=5.1%, Z3=5.2%,Z_3=5.2\%,Z3​=5.2%,The 1.5-ye bonha $100 favalue, 6% semiannucoupon payment. Calculate the bonprice: A.$98.34. B.$99.73. C.$100.52. $101.05. is correct. 考点Interest Rate解析lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05{l}B=3\times e^{\lbrack{(-0.05/2)}\times1\rbrack}+3\times e^{\lbrack{(-0.051/2)}\times2\rbrack}+103\times e^{\lbrack{(-0.052/2)}\times3\rbrack}\\=2.93+2.85+95.27=\$101.05lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05 请问“Assume ththe annucontinuously compounspot rates are: Z1=5%, Z2​=5.1%, Z3=5.2%,”这里说的是年化连续复利的折现率分别为Z1 Z2 Z3对吧？1.5yebon每半年的现金流折现率为什么不是(Z1)/2,Z1,(Z2)/2呢？

NO.PZ2019052801000034问题如下Assume ththe annucontinuously compounspot rates are: Z1=5%,Z_1=5\%,Z1​=5%, Z2=5.1%,Z_2=5.1\%,Z2​=5.1%, Z3=5.2%,Z_3=5.2\%,Z3​=5.2%,The 1.5-ye bonha $100 favalue, 6% semiannucoupon payment. Calculate the bonprice: A.$98.34.B.$99.73.C.$100.52.$101.05.is correct. 考点Interest Rate解析lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05{l}B=3\times e^{\lbrack{(-0.05/2)}\times1\rbrack}+3\times e^{\lbrack{(-0.051/2)}\times2\rbrack}+103\times e^{\lbrack{(-0.052/2)}\times3\rbrack}\\=2.93+2.85+95.27=\$101.05lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05 解题过程和正确答案。谢谢

NO.PZ2019052801000034问题如下 Assume ththe annucontinuously compounspot rates are: Z1=5%,Z_1=5\%,Z1​=5%, Z2=5.1%,Z_2=5.1\%,Z2​=5.1%, Z3=5.2%,Z_3=5.2\%,Z3​=5.2%,The 1.5-ye bonha $100 favalue, 6% semiannucoupon payment. Calculate the bonprice: A.$98.34.B.$99.73.C.$100.52.$101.05.is correct. 考点Interest Rate解析lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05{l}B=3\times e^{\lbrack{(-0.05/2)}\times1\rbrack}+3\times e^{\lbrack{(-0.051/2)}\times2\rbrack}+103\times e^{\lbrack{(-0.052/2)}\times3\rbrack}\\=2.93+2.85+95.27=\$101.05lB=3×e[(−0.05/2)×1]+3×e[(−0.051/2)×2]+103×e[(−0.052/2)×3]=2.93+2.85+95.27=$101.05 说了semiannual6%.那就是半年coupon就是六为啥是三，另外我觉得公式是下面为啥错了