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何小建 · 2019年06月28日

问一道题:NO.PZ2016062402000016

问题如下图:

    

选项:

A.

B.

C.

D.

解释:


还是不太理解,poissonfen分布方差等于兰塔,不是因为1-p趋jin近于1木,因此成功的gai'l概率是p。趋紧zheng'tzheng'tai正态分布也不能说明p就是成功的概率,万一是错误的比例很高呢。

1 个答案

orange品职答疑助手 · 2019年06月29日

同学你好,这道题考察的主要是原版书里的这个结论。当n很大,p趋近于0时,二项分布可以被泊松分布很好的估计。而如果λ很大,那么泊松分布可以被正态分布所估计。λ很大才可以,所以就选了λ趋近于1。这里的成功率它指的是 λ,而不是p。

可能不同教材有一些不一样,建议同学把这个知识点单独记一下,还是遵循原版书比较保险的。


Potatowpn · 2019年07月02日

为什么拉姆他最大只能趋近于1?

orange品职答疑助手 · 2019年07月03日

这个是在题目里选的,它越大越趋于正态分布,所以就选了选项里最大的1

$eba🚀 · 2019年08月01日

这里的success rate应该是p。根据选项的意思,只有p接近于1的时候,在n很大的情况下,才能保证np很大。

orange品职答疑助手 · 2019年08月01日

不是啊,只有λ大就可以了,并不是要p接近于1,泊松分布才能被正态分布拟合

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