开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

Roxanne_104 · 2019年06月11日

问一道题:NO.PZ2019040801000025 [ FRM I ]

问题如下图:

选项:

A.

B.

C.

D.

解释:

怎么知道96%的置信区间是11到35

1 个答案

品职答疑小助手雍 · 2019年06月12日

同学你好,11到35是题目给的已知条件。

  • 1

    回答
  • 0

    关注
  • 349

    浏览
相关问题

NO.PZ2019040801000025 问题如下 Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to: A.1.96. B.3.58. C.6.12. 10.50. C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米 如题,请老师赐教,盼复,谢谢

2024-09-11 14:38 1 · 回答

NO.PZ2019040801000025 问题如下 Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to: A.1.96. B.3.58. C.6.12. 10.50. C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米 题目没有提到ranmly select,另外sample mean是在11和35之间,求出来的为什么不是sample s直接就是标准误?

2024-04-18 11:00 1 · 回答

NO.PZ2019040801000025问题如下Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to:A.1.96.B.3.58.C.6.12.10.50.C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米看过之前类似提问,感觉没说清楚

2024-03-25 23:29 1 · 回答

NO.PZ2019040801000025 问题如下 Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to: A.1.96. B.3.58. C.6.12. 10.50. C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米 如题

2024-03-19 10:12 1 · 回答

NO.PZ2019040801000025问题如下Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to:A.1.96.B.3.58.C.6.12.10.50.C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米老师,这个样本(容量200)的均值为什么是(11+35)/2呢?如果这么算不就相当样本容量2棵树,一颗高度11,一颗高度35?

2024-02-25 21:08 3 · 回答