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怎么知道96%的置信区间是11到35
NO.PZ2019040801000025 问题如下 Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to: A.1.96. B.3.58. C.6.12. 10.50. C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米 如题,请老师赐教,盼复,谢谢
NO.PZ2019040801000025 问题如下 Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to: A.1.96. B.3.58. C.6.12. 10.50. C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米 题目没有提到ranmly select,另外sample mean是在11和35之间,求出来的为什么不是sample s直接就是标准误?
NO.PZ2019040801000025问题如下Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to:A.1.96.B.3.58.C.6.12.10.50.C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米看过之前类似提问,感觉没说清楚
NO.PZ2019040801000025 问题如下 Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to: A.1.96. B.3.58. C.6.12. 10.50. C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米 如题
NO.PZ2019040801000025问题如下Assuming the height of a tree in a forest follows a normstribution, there are more th10,000 trees. The sample size of test is 200, the 95% confinintervof the sample meof the height is 11 to 35 meters baseon a z-statistithe stanrerror of meheight is closest to:A.1.96.B.3.58.C.6.12.10.50.C is correct.考点The centrlimit theorem (CLT)解析95%的置信区间是11到 35,z值是1.96.平均数为0.5*(11+35)=23.所以置信区间是23 ± 1.96sx, sx是标准误。23+1.96sx等于35,sx等于6.12米老师,这个样本(容量200)的均值为什么是(11+35)/2呢?如果这么算不就相当样本容量2棵树,一颗高度11,一颗高度35?