问题如下图：
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解释：
此题为什么不能通过t0的价值反求node1-2
NO.PZ2018123101000049 问题如下 Exhibit 3 presents most of the ta of a binomilognorminterest rate tree. Exhibit 4 presents most of the ta of the implievalues for a four-year, option-free, annupbonwith a 2.5% coupon baseon the information in Exhibit 3.Baseon the information in Exhibits 3 an4, the bonpriin euros No 1–2 in Exhibit 4 is to: A.102.7917 B.104.8640 C.105.2917 A is correct.考点考察利用利率二叉树定价解析: 想要得到节点1-2的债券价值，用到的数据有该节点右边的数据，即节点2-2，节点2-3的债券价值和Coupon，以及第一年末至第二年的Forwarrate。通过对未来债券价值的折现求得该节点1-2的债券价值value = {2.5+(0.5×101.5168+0.5×102.1350)} / 1.014925 = 102.7917 为什么只加了一个2.5？
NO.PZ2018123101000049问题如下Exhibit 3 presents most of the ta of a binomilognorminterest rate tree. Exhibit 4 presents most of the ta of the implievalues for a four-year, option-free, annupbonwith a 2.5% coupon baseon the information in Exhibit 3.Baseon the information in Exhibits 3 an4, the bonpriin euros No 1–2 in Exhibit 4 is to:A.102.7917B.104.8640C.105.2917 A is correct.考点考察利用利率二叉树定价解析: 想要得到节点1-2的债券价值，用到的数据有该节点右边的数据，即节点2-2，节点2-3的债券价值和Coupon，以及第一年末至第二年的Forwarrate。通过对未来债券价值的折现求得该节点1-2的债券价值value = {2.5+(0.5×101.5168+0.5×102.1350)} / 1.014925 = 102.7917 能否用t0和t1的数据推出答案？只能从后往前推么
104.8640 105.2917 A is correct. 考点考察利用利率二叉树定价 解析: 想要得到节点1-2的债券价值，用到的数据有该节点右边的数据，即节点2-2，节点2-3的债券价值和Coupon，以及第一年末至第二年的Forwarrate。通过对未来债券价值的折现求得该节点1-2的债券价值 value = {2.5+(0.5×101.5168+0.5×102.1350)} / 1.014925 = 102.7917 这个题不对啊？我是从后面推了一下尝试的，后面从一开始到102.1350都是不含着这个时点本身的2.5的。都是只有在往前面折算的时候单独加了2.5。为什么这个点No1-2要把2.5加在里面显示？这与其他的数字显示不一致啊
NO.PZ2018123101000049 问题如下 Exhibit 3 presents most of the ta of a binomilognorminterest rate tree. Exhibit 4 presents most of the ta of the implievalues for a four-year, option-free, annupbonwith a 2.5% coupon baseon the information in Exhibit 3.Baseon the information in Exhibits 3 an4, the bonpriin euros No 1–2 in Exhibit 4 is to: A.102.7917 B.104.8640 C.105.2917 A is correct.考点考察利用利率二叉树定价解析: 想要得到节点1-2的债券价值，用到的数据有该节点右边的数据，即节点2-2，节点2-3的债券价值和Coupon，以及第一年末至第二年的Forwarrate。通过对未来债券价值的折现求得该节点1-2的债券价值value = {2.5+(0.5×101.5168+0.5×102.1350)} / 1.014925 = 102.7917 NO.PZ2018123101000049问题如下Exhibit 3 presents most of the ta of a binomilognorminterest rate tree. Exhibit 4 presents most of the ta of the implievalues for a four-year, option-free, annupbonwith a 2.5% coupon baseon the information in Exhibit 3.Baseon the information in Exhibits 3 an4, the bonpriin euros No 1–2 in Exhibit 4 is to:A.102.7917B.104.8640C.105.2917A is correct.考点考察利用利率二叉树定价解析: 想要得到节点1-2的债券价值，用到的数据有该节点右边的数据，即节点2-2，节点2-3的债券价值和Coupon，以及第一年末至第二年的Forwarrate。通过对未来债券价值的折现求得该节点1-2的债券价值value = {2.5+(0.5×101.5816+0.5×102.1350)} / 1.014925 = 102.7917按照何老师课程里讲的，求no要加上当期coupon，求value则不用，为什么这里求no却不用加上当期coupon？
NO.PZ2018123101000049 为什么不能用上面一个数据除以e的2倍西格玛次方？
