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粉红豹 · 2019年01月05日

问一道题:NO.PZ2018103102000085 [ CFA II ]

问题如下图:

选项:

A.

B.

C.

解释:

老师,这道题目计算很常规

但是很多次都发现,如果我留小数点在后面6位,算出来结果差了也不少了。

问下考试时候中间部分的计算需要注意留几位小数呢

2 个答案

薛定谔的蝎子 · 2019年11月10日

答案明显保留的两位小数,比较坑爹

maggie_品职助教 · 2019年01月05日

1、二级考试计算器尽量设置小数位大于等于6位,越多越精确,但不强求

2、既然是6位小数,那么中间计算出来的也就会自动保留成6位,你只需要是计算机的“存储”“调取”功能即可。

3、只要计算正确,在考试中选项3个的差别会很大,不会因为保留几位小数而出现选不出答案的情况(这个可以绝对放心)

4、如果选不出答案,一定是算错了。

加油。

粉红豹 · 2019年04月05日

D1=0.55,D2=0.605,D3=0.635,D4=0.667,V4=9.8146, 按计算器,CF1-CF3如前,CF4=0.667+9.8146=10.4816, 最后结果是 8.636。老师,我算了好多次了,我觉得这道题目的答案确实留小数留的太少,导致算出来差的挺多。

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NO.PZ2018103102000085 问题如下 Matt is evaluating the value of Company M using the vinscount mol. The most recent vinanthe requirerate of return are $0.5 per share an10%, respectively. The company will experiena highly growth of 10% the first two years, followea 5% of growth in another two years. Thereafter, the vingrowth rate woul3% per yeinto the infinite future. What's the value of Company M? A.$8.16 B.$8.64 C.$9.67 考点Three Stage Mol解析PV4=×(1+gL)r−gL=0.667×(1+3%)10%−3%=$9.8146PV_4=\frac{4\times\left(1+g_L\right)}{r-g_L}=\frac{0.667\times\left(1+3\%\right)}{10\%-3\%}=\$9.8146PV4​=r−gL​​×(1+gL​)​=10%−3%0.667×(1+3%)​=$9.8146P=0.551.1+0.6051.12+0.635251.13+0.667+9.81461.14=$8.64P=\frac{0.55}{1.1}+\frac{0.605}{1.1^2}+\frac{0.63525}{1.1^3}+\frac{0.667+9.8146}{1.1^4}=\$8.64P=1.10.55​+1.120.605​+1.130.63525​+1.140.667+9.8146​=$8.64 具体做法,画图1,先把所有的vin出来 =0.55,=0.605,=0.635,=0.667,=0.687.2,求P4=/10%-3%=9.815前面都没问题,接下来就和答案不一样,麻烦老师指出我的错误3,求P2=/10%-5%=12.74,求第一阶段的NPV,用计算器输入,CF0=1,CF1=0.55,CF2=0.605+12.7,I/Y=10,NPV=11.50

2024-05-13 16:27 1 · 回答

NO.PZ2018103102000085 问题如下 Matt is evaluating the value of Company M using the vinscount mol. The most recent vinanthe requirerate of return are $0.5 per share an10%, respectively. The company will experiena highly growth of 10% the first two years, followea 5% of growth in another two years. Thereafter, the vingrowth rate woul3% per yeinto the infinite future. What's the value of Company M? A.$8.16 B.$8.64 C.$9.67 考点Three Stage Mol解析PV4=×(1+gL)r−gL=0.667×(1+3%)10%−3%=$9.8146PV_4=\frac{4\times\left(1+g_L\right)}{r-g_L}=\frac{0.667\times\left(1+3\%\right)}{10\%-3\%}=\$9.8146PV4​=r−gL​​×(1+gL​)​=10%−3%0.667×(1+3%)​=$9.8146P=0.551.1+0.6051.12+0.635251.13+0.667+9.81461.14=$8.64P=\frac{0.55}{1.1}+\frac{0.605}{1.1^2}+\frac{0.63525}{1.1^3}+\frac{0.667+9.8146}{1.1^4}=\$8.64P=1.10.55​+1.120.605​+1.130.63525​+1.140.667+9.8146​=$8.64 老师您好,这道题我用计算器NPV功能计算的,发现CF0如果输入0.5的话计算结果就不正确,输入0就和答案一样。请问这里的第0期的CF0为什么不用输入0.5这个数值呢?

2024-05-09 23:57 1 · 回答

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2023-08-08 18:19 1 · 回答

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2020-05-16 18:24 1 · 回答

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2020-03-22 23:49 1 · 回答