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张大龙 · 2025年01月15日

老师你好,这题我就没太明白啥意思,能给讲讲不,谢谢

NO.PZ2024120401000006

问题如下:

The monthly return on a hedge fund portfolio with USD 1 billion in assets is N(0.02, 0.0003). What would the line of credit need to be to ensure that the firm’s loss was less than the line of credit in 99.9% of months (or equivalently, larger than the LOC in 0.1% of months) ?

Note: Pr(Z < z) = 99.9% means z= -3.09

选项:

A.

17.3 million

B.

33.46 million

C.

20 million

D.

60 million

解释:

The monthly change in portfolio value will also be normally distributed with a mean of 0.02 * USD 1 billion = USD 20 million and a variance of 0.0003 * 1 billion2 = 300 trillion. The standard deviation of the gain will be USD 17.3 million.

First, we find the quantile where Pr(Z < z) = 99.9%, which gives z =-3.09. This is then scaled to the distribution of the change in the value of the portfolio by multiplying by the standard deviation and adding the mean, 17.3 *(-3.09) + 20 = -33.46. The fund would need a line of credit of USD 33.46 million to have a 99.9% chance of having loss below this level.

老师你好,这题我就没太明白啥意思,能给讲讲不,谢谢

1 个答案

李坏_品职助教 · 2025年01月16日

嗨,努力学习的PZer你好:


题目是问你,信用额度(line of credit )应该达到多少钱,才能确保公司的损失在99.9%的概率上小于信用额度?

其实就是让你找出99.9%对应的极端损失是多少。


首先找出在标准正态分布下,99.9%对应的左尾分布值是Z=-3.09。参考下图:

既然考察的是损失,那就只需要看左尾。红色阴影部分的面积占所有阴影面积的0.1%,而黑色阴影部分的面积是占了99.9%. 左侧的极端损失对应的分位数Z = -3.09。


但这个Z是标准正态分布的Z值(标准正态分布指的是均值为0,方差为1的正态分布),这道题的分布函数不是标准正态分布,其均值 =  0.02 * USD 1 billion = 20,方差 =  0.0003 * 1 billion = 300,所以标准差=根号300 = 17.3


假设99%概率下的极端损失是Z2,那么根据标准化的公式,-3.09 = (Z2-均值)/ 标准差,所以Z2 = -3.09*17.3+20= -33.46



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虽然现在很辛苦,但努力过的感觉真的很好,加油!

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