NO.PZ2016031001000070
问题如下：
Bond G, described in the exhibit below, is sold for settlement on 16 June 2014.
Annual Coupon 5%
Coupon Payment Frequency Semiannual
Interest Payment Dates 10 April and 10 October
Maturity Date 10 October 2016
Day Count Convention 30/360
Annual Yield-to-Maturity 4%
The accrued interest per 100 of par value for Bond G on the settlement date of 16 June 2014 is closest to:
选项：
A.0.46.
B.0.73.
C.0.92.
解释：
C is correct.
The accrued interest per 100 of par value is closest to 0.92. The accrued interest is determined in the following manner: The accrued interest period is identified as66/180. The number of days between 10 April 2014 and 16 June 2014 is 66 days based on the 30/360 day count convention. (This is 20 days remaining in April + 30 days in May +16 days in June = 66 days total). The number of days between coupon periods is assumed to be 180 days using the 30/360 day convention.
where:
t = number of days from the last coupon payment to the settlement date
T = number of days in the coupon period
t/T= fraction of the coupon period that has gone by since the last payment
PMT = coupon payment per period
考点：accrued interest
解析：accrued interest=coupon×t/T=(5/2)×(66/180)=0.92，故选项C正确。
由于债券半年付息，所以一期的coupon是2.5。t=66，代表的是trading day和上一个付息日之间的天数，4月10号到6月16号之间是66天。T代表的就是两个付息日之间的天数，由于我们现在是30/360，所以半年天数就是180天。将上述数据代入accrued interest的公式即可。
accrued interest为什么在10/4/2014-16/6/2014这段？
