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ciaoyy · 2018年08月15日

问一道题:NO.PZ2016082402000028

问题如下图:

    

选项:

A.

B.

C.

D.

解释:


可以这样理解吗?已有call市场价为3元,低于put-call parity合成的call4.19元。因此买已有call,short合成call。而合成的call=P+S-K,那么short头寸下,整个头寸就变为-P-S+K。所以综上,要long K和市场call,short P和S?

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orange品职答疑助手 · 2018年08月16日

同学你好,可以的

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NO.PZ2016082402000028 问题如下 The current priof stoAis $42 anthe call option with a strike $44 is trang $3. Expiration is in one year. The corresponng put is price$2. Whiof the following trang strategies will result in arbitrage profits? Assume ththe risk-free rate is 10% anththe risk-free boncshortecostlessly. There are no transaction costs. Long position in both the call option anthe stock, anshort position in the put option anrisk-free bon Long position in both the call option anthe put option, anshort position in the stoanrisk-free bon Long position in both the call option anthe risk-free bon anshort position in the stoanthe put option Long position in both the put option anthe risk-free bon anshort position in the stoanthe call option ANSWER: CAnswers A anB have payoffs thpenon the stopriantherefore cannot create arbitrage profits. Put-call parity says thc−p=3−2=$1c-p=3-2=\$1c−p=3−2=$1 shoulequals S−Ke−rτ=42−44×0.9048=$2.19S-Ke^{-r\tau}=42-44\times0.9048=\$2.19S−Ke−rτ=42−44×0.9048=$2.19. The call option is cheap. Therefore buy the call anhee it selling the stock, for the upsi. The benefit from selling the stoif S goes wn is offset selling a put. 时间为一年,为什么是Ke^−rT 而不是Ke^tT 呢

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