请问0.456对吗？怎么算出的标准差带进去不对呢

NO.PZ2023091601000105问题如下 Suppose thwe have the following ta on three features for eachof three banks, anC:Scale the featuresusing normalization anstanrzation. Stanrzationinvolves subtracting the meof the observations across the three banks aniving their stanrviation separately for eafeature. Thenormalization involves subtracting the minimum anving the fferencebetween the maximum anminimum.example,unrtaking the stanrzation for bank A anthe customers feature, thecalculation woul Similarly, thenormalization calculation for bank A anthe customers feature woul The full set ofstanrzations annormalizations is 同学你好，1.2 6 0.5这三个数的均值是2.566667。这里标准化分子可以取绝对值的，所以2.56667-1.2=1.36667。分母其实就是样本标准差，因为所有的银行才是全集，这三家银行只是样本。样本标准差的计算就是1.2 、 6 、 0.5 这三个数分别减去2.56667，得到的三个数的平方和即17.92667除以n-1，这里3个样本，所以n=3，得到8.96333再开方等于2.993883即是样本标准差。1.36667/2.993883=0.456486老师这是您对其他学生的解答您是不是算反了？讲的公式是“（X-均值）/标准差”您算的是（均值-X）/标准差。而且知识框架图给的公式，分母是总体方差，您这里用的又是样本方差…到底该用啥？

NO.PZ2023091601000105问题如下 Suppose thwe have the following ta on three features for eachof three banks, anC:Scale the featuresusing normalization anstanrzation. Stanrzationinvolves subtracting the meof the observations across the three banks aniving their stanrviation separately for eafeature. Thenormalization involves subtracting the minimum anving the fferencebetween the maximum anminimum.example,unrtaking the stanrzation for bank A anthe customers feature, thecalculation woul Similarly, thenormalization calculation for bank A anthe customers feature woul The full set ofstanrzations annormalizations is 这道题用计算器过程怎么计算