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考拉 · 2024年01月24日

关于这个公式中的Spread, EXR = (s × t) – (∆s × SD) – (t × p × L)

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NO.PZ202209060200004203

问题如下:

The bond in Exhibit 2 with the best relative value is most likely:

选项:

A.Bond D. B.Bond E. C.Bond F.

解释:

Solution

A is correct. Bond D has the best relative value; its expected excess return (EXR) has the smallest loss given the expectation that credit spreads are going to widen by 25 bps (the change in the Z-spread). The expected excess return calculation is as follows:EXR = (s × t) – (∆s × SD) – (t × p × L)where

s = Z-spread

t = Holding period

SD = Spread duration

p = Probability of default

L = Loss severity

Calculations are as follows:

B is incorrect because Bond D has the best expected excess return.

C is incorrect because Bond D has the best expected excess return.

EXR = (s × t) – (∆s × SD) – (t × p × L),关于这个, 不同的题考了好几遍了,有些是用oas, 有些用zpread, 请问这个公式的的Spread是不是本来就可以自定义?yield spread,g-spread, asw等理论上都可以用?

1 个答案

pzqa015 · 2024年01月24日

嗨,从没放弃的小努力你好:


是的,理论上都可以作为OAS,因为OAS本身也是一种spread

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