开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

17783510317 · 2023年11月01日

题目给的是bond b 3的评级

* 问题详情,请 查看题干

NO.PZ201812310200000105

问题如下:

Bond B3 will have a modified duration of 2.75 at the end of the year. Based on the representative one-year corporate transition matrix in Exhibit 7 of the reading and assuming no default, how should the analyst adjust the bond’s yield to maturity (YTM) to assess the expected return on the bond over the next year?

选项:

A.

Add 7.7 bps to YTM.

B.

Subtract 7.7 bps from YTM.

C.

Subtract 9.0 bps from YTM.

解释:

B is correct. For each possible transition, the expected percentage price change, computed as the product of the modified duration and the change in the spread as per Exhibit 7 of the reading, is calculated as follows:

From AA to AAA: –2.75 × (0.60% – 0.90%) = +0.83%

From AA to A: –2.75 × (1.10% – 0.90%) = –0.55%

From AA to BBB: –2.75 × (1.50% – 0.90%) = –1.65%

From AA to BB: –2.75 × (3.40% – 0.90%) = –6.88%

From AA to B: –2.75 × (6.50% – 0.90%) = –15.40%

From AA to C: –2.75 × (9.50% – 0.90%) = –23.65%

The expected percentage change in the value of the AA rated bond is computed by multiplying each expected percentage price change for a possible credit transition by its respective transition probability given in Exhibit 7 of the reading, and summing the products:

(0.0150 × 0.83%) + (0.8800 × 0%) + (0.0950 × –0.55%) + (0.0075 × –1.65%) + (0.0015 × –6.88%) + (0.0005 × –15.40%) + (0.0003 × –23.65%)= –0.0774%.

Therefore, the expected return on the bond over the next year is its YTM minus 0.0774%, assuming no default.

可答案以bond a 作为初始spread. 难道duration 对于不同评级的债券都是一样的?

1 个答案

pzqa015 · 2023年11月03日

嗨,爱思考的PZer你好:


第一个表格说了Bond3是AA评级,所以概率要用AA那一行的概率,提问那段话说了Bond B3 will have a modified duration of 2.75,所以,久期就是2.75呀。这道题涉及不到初始的spread,我们只需要计算不同概率下评级变化带来的spread变化,乘久期后就是ytm的变化。

----------------------------------------------
就算太阳没有迎着我们而来,我们正在朝着它而去,加油!

  • 1

    回答
  • 0

    关注
  • 160

    浏览
相关问题

NO.PZ201812310200000105 Subtra7.7 bps from YTM. Subtra9.0 bps from YTM. B is correct. For eapossible transition, the expectepercentage prichange, computethe proof the mofieration anthe change in the spreper Exhibit 7 of the reang, is calculatefollows: From to AA–2.75 × (0.60% – 0.90%) = +0.83% From to –2.75 × (1.10% – 0.90%) = –0.55% From to BB–2.75 × (1.50% – 0.90%) = –1.65% From to B–2.75 × (3.40% – 0.90%) = –6.88% From to –2.75 × (6.50% – 0.90%) = –15.40% From to –2.75 × (9.50% – 0.90%) = –23.65% The expectepercentage change in the value of the ratebonis computemultiplying eaexpectepercentage prichange for a possible cret transition its respective transition probability given in Exhibit 7 of the reang, ansumming the procts: (0.0150 × 0.83%) + (0.8800 × 0%) + (0.0950 × –0.55%) + (0.0075 × –1.65%) + (0.0015 × –6.88%) + (0.0005 × –15.40%) + (0.0003 × –23.65%)= –0.0774%. Therefore, the expectereturn on the bonover the next yeis its YTM minus 0.0774%, assuming no fault. 我理解算出来的答案是expectereturn of prichange,但它和调整YTM有什么关系?我转不过来了…

2022-03-04 23:12 1 · 回答

NO.PZ201812310200000105 Subtra7.7 bps from YTM. Subtra9.0 bps from YTM. B is correct. For eapossible transition, the expectepercentage prichange, computethe proof the mofieration anthe change in the spreper Exhibit 7 of the reang, is calculatefollows: From to AA–2.75 × (0.60% – 0.90%) = +0.83% From to –2.75 × (1.10% – 0.90%) = –0.55% From to BB–2.75 × (1.50% – 0.90%) = –1.65% From to B–2.75 × (3.40% – 0.90%) = –6.88% From to –2.75 × (6.50% – 0.90%) = –15.40% From to –2.75 × (9.50% – 0.90%) = –23.65% The expectepercentage change in the value of the ratebonis computemultiplying eaexpectepercentage prichange for a possible cret transition its respective transition probability given in Exhibit 7 of the reang, ansumming the procts: (0.0150 × 0.83%) + (0.8800 × 0%) + (0.0950 × –0.55%) + (0.0075 × –1.65%) + (0.0015 × –6.88%) + (0.0005 × –15.40%) + (0.0003 × –23.65%)= –0.0774%. Therefore, the expectereturn on the bonover the next yeis its YTM minus 0.0774%, assuming no fault. 0.015 0.095 0.0075……是怎么来的呢

2021-03-02 11:21 2 · 回答

问一道题:NO.PZ201812310200000105

2020-05-27 10:45 1 · 回答

问一道题:NO.PZ201812310200000105

2020-03-12 21:37 1 · 回答