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fdzh · 2023年11月01日

能否请展示这题的计算过程

NO.PZ2023091601000059

问题如下:

Hedge Fund has been in existence for two years. Its average monthly return has been 6% with a standard deviation of 5%. Hedge Fund has a stated objective of controlling volatility as measured by the standard deviation of monthly returns. You are asked to test the null hypothesis that the volatility of Hedge Fund’s monthly returns is equal to 4% versus the alternative hypothesis that the volatility is greater than 4%. Assuming that all monthly returns are independently and identically normally distributed, and using the tables below, what is the correct test to be used and what is the correct conclusion at the 2.5% level of significance?

选项:

A.

t-test; reject the null hypothesis

B.

Chi-square test; reject the null hypothesis

C.

t-test; do not reject the null hypothesis

D.

Chi-square test; do not reject the null hypothesis

解释:

Null Hypothesis:

Alternative Hypothesis:

Critical Region, reject the null if:

Therefore, you would not reject the null hypothesis. A chi-square test is a statistical hypothesis test whereby the sampling distribution of the test statistic is a chi-squared distribution when the null hypothesis is true.

我想与自己的计算对照一下?谢谢

1 个答案

李坏_品职助教 · 2023年11月01日

嗨,从没放弃的小努力你好:


the null hypothesis that the volatility of Hedge Fund’s monthly returns is equal to 4% versus the alternative hypothesis that the volatility is greater than 4%. 所以H0是:σ≤4%,H1是:σ>4%. 检验单个样本的方差大于或小于某个数字,要用one-tailed的chi square检验。

样本是2年的monthly数据,所以样本容量是24个。那么df = n-1 = 23. 查表,对应的df=23并且one-tailed prob等于2.5%的阈值是38.0757.

检验统计量 = (n-1)*5%^2 / 4%^2 = 35.9375. 这个数字小于38.0757,所以无法拒绝H0.


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虽然现在很辛苦,但努力过的感觉真的很好,加油!