开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

🧸苏小糖yb💚 · 2023年10月25日

为什么d的计算不用考虑R

NO.PZ2020021205000030

问题如下:

The futures price of an asset is USD 20, and the volatility of the futures price is 30%. Calculate the value of a put option to sell futures in three months for USD 22. The risk-free rate is 4%.

解释:

In this case F0 = 20, K = 22, r = 0.04, u = 0.3,

T = 0.25, and Equation (15.13) gives

d,=ln(20/22)  +  (0.32/2)  X  0.250.30.25\frac{\ln(20/22)\;+\;(0.3^2/2)\;X\;0.25}{0.3\sqrt{0.25}}= -0.5604

d2 =ln(20/22)    (0.32/2)  X  0.250.30.25\frac{\ln(20/22)\;-\;(0.3^2/2)\;X\;0.25}{0.3\sqrt{0.25}}= -0.7104

put =22*EXP(-4%*0.25)*N(0.7104)-20*EXP(-4%*0.25)*N(0.5604)=2.48

为什么d不考虑R 但是计算P价格的时候要考虑R

2 个答案

李坏_品职助教 · 2023年10月26日

嗨,从没放弃的小努力你好:


经过我们的研究,这个题目说的是future的期权,也就是期货的期权。这个确实是不需要包含r的:

----------------------------------------------
就算太阳没有迎着我们而来,我们正在朝着它而去,加油!

李坏_品职助教 · 2023年10月25日

嗨,努力学习的PZer你好:


这个题目答案有问题,多谢同学提醒,我去反馈一下。

正确的计算put option价值的公式如下:

----------------------------------------------
努力的时光都是限量版,加油!

  • 2

    回答
  • 0

    关注
  • 183

    浏览
相关问题

NO.PZ2020021205000030 问题如下 The futures priof asset is US20, anthe volatility of the futures priis 30%. Calculate the value of a put option to sell futures in three months for US22. The risk-free rate is 4%.p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 9.0px Helveticcolor: #463f46}span.s1 {color: #4b5768}span.s2 {color: #6b5147} In this case F0 = 20, K = 22, r = 0.04, u = 0.3,p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4134}span.s1 {font: 8.5px Helvetica}span.s2 {font: 5.5px Helvetica}span.s3 {color: #696b}span.s4 {font: 9.5px Helvetica}span.s5 {color: #675248}T = 0.25, anEquation (15.13) gives=ln⁡(20/22)  +  (0.32/2)  X  0.250.30.25\frac{\ln(20/22)\;+\;(0.3^2/2)\;X\;0.25}{0.3\sqrt{0.25}}0.30.25​ln(20/22)+(0.32/2)X0.25​= -0.5604p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4a4449}span.s1 {color: #6b6b6b}p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 5.5px Helveticcolor: #4c474span.s1 {font: 8.5px Helvetica}span.s2 {font: 8.0px Helvetica}span.s3 {font: 8.0px Helveticcolor: #a29f9e} =ln⁡(20/22)  −  (0.32/2)  X  0.250.30.25\frac{\ln(20/22)\;-\;(0.3^2/2)\;X\;0.25}{0.3\sqrt{0.25}}0.30.25​ln(20/22)−(0.32/2)X0.25​= -0.7104p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4c474p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4a444b}put =22*EXP(-4%*0.25)*N(0.7104)-20*EXP(-4%*0.25)*N(0.5604)=2.48p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4a444b}p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4e464c}span.s1 {color: #373a}span.s2 {color: #777377}span.s3 {color: #636b73}span.s4 {font: 5.0px Helvetic 老师,如题,是我哪里理解错了吗

2024-09-04 15:41 1 · 回答

NO.PZ2020021205000030问题如下The futures priof asset is US20, anthe volatility of the futures priis 30%. Calculate the value of a put option to sell futures in three months for US22. The risk-free rate is 4%.p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 9.0px Helveticcolor: #463f46}span.s1 {color: #4b5768}span.s2 {color: #6b5147} In this case F0 = 20, K = 22, r = 0.04, u = 0.3,p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4134}span.s1 {font: 8.5px Helvetica}span.s2 {font: 5.5px Helvetica}span.s3 {color: #696b}span.s4 {font: 9.5px Helvetica}span.s5 {color: #675248}T = 0.25, anEquation (15.13) gives=ln⁡(20/22)  +  (0.32/2)  X  0.250.30.25\frac{\ln(20/22)\;+\;(0.3^2/2)\;X\;0.25}{0.3\sqrt{0.25}}0.30.25​ln(20/22)+(0.32/2)X0.25​= -0.5604p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4a4449}span.s1 {color: #6b6b6b}p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 5.5px Helveticcolor: #4c474span.s1 {font: 8.5px Helvetica}span.s2 {font: 8.0px Helvetica}span.s3 {font: 8.0px Helveticcolor: #a29f9e} =ln⁡(20/22)  −  (0.32/2)  X  0.250.30.25\frac{\ln(20/22)\;-\;(0.3^2/2)\;X\;0.25}{0.3\sqrt{0.25}}0.30.25​ln(20/22)−(0.32/2)X0.25​= -0.7104p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4c474p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4a444b}p=22 /spe−0.04∗0.25 /spe^{-0.04\ast0.25} /spe−0.04∗0.25N(O.71O4)p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4e464c}span.s1 {color: #373a}span.s2 {color: #777377}span.s3 {color: #636b73}span.s4 {font: 5.0px Helvetica}- 20 spe−0.04∗0.25 spe^{-0.04\ast0.25} spe−0.04∗0.25N(O.56O4) = 2.48p.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 8.0px Helveticcolor: #4a444b}答案后两行是乱码,请老师更正。

2022-03-24 18:45 1 · 回答

这题怎么都算不对,老师能帮忙写一下过程吗

2020-03-10 16:21 1 · 回答