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Maxy · 2023年10月18日

请问请问1.6384和0.5461怎么算出来的?

NO.PZ2019010402000021

问题如下:

A manager plans to estimate the value of American-style put option by using two-period binomial model. The current stock price is $32, and exercise price of put option is $32.The up factor is 1.12, and the down factor is 0.92. The risk-free rate is 5%. The value of this put option is:

选项:

A.

0.5461

B.

0.8533

C.

1.0432

解释:

B is correct.

考点:二叉树求value

解析:

πu=1+Rfdud=1+5%0.921.120.92=0.65\pi\text{u}=\frac{1+R_f-d}{u-d}=\frac{1+5\%-0.92}{1.12-0.92}=0.65

画二叉树

这一题是美式期权,在t=1时执行,put的价值更高(=32-29.44=2.56),所以投资者会选择提前执行。此时

P0=2.56×0.35+0×0.651.05=0.8533P_0=\frac{2.56\times0.35+0\times0.65}{1.05}=0.8533

如题

1 个答案
已采纳答案

李坏_品职助教 · 2023年10月18日

嗨,爱思考的PZer你好:


1.6384就是后面两个节点的Put option价值的折现:

1.6384= (0 * 0.65 + 4.9152 * 0.35)/1.05, 但是这个价值明显小于提前行权带来的2.56,所以在二叉树里面被2.56替换了。


而0.5461则是“假设后面没有提前行权的话,0时刻的put option价值”,

0.5461 = (0*0.65 + 1.6384*0.35)/1.05

----------------------------------------------
就算太阳没有迎着我们而来,我们正在朝着它而去,加油!

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NO.PZ2019010402000021问题如下A manager plans to estimate the value of American-style put option using two-periobinomimol. The current stopriis $32, anexercise priof put option is $32.The up factor is 1.12, anthe wn factor is 0.92. The risk-free rate is 5%. The value of this put option is:A.0.5461B.0.8533C.1.0432B is correct.考点二叉树求value解析πu=1+Rf−−1+5%−0.921.12−0.92=0.65\pi\text{u}=\frac{1+R_f-{u-=\frac{1+5\%-0.92}{1.12-0.92}=0.65πu=u−+Rf​−=1.12−0.921+5%−0.92​=0.65画二叉树这一题是美式期权,在t=1时执行,put的价值更高(=32-29.44=2.56),所以投资者会选择提前执行。此时P0=2.56×0.35+0×0.651.05=0.8533P_0=\frac{2.56\times0.35+0\times0.65}{1.05}=0.8533P0​=1.052.56×0.35+0×0.65​=0.85331.p++、p+-和p--的公式是什么?2.请在纸上写一下完整过程,越详细越好。

2023-10-21 15:57 1 · 回答

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2022-08-07 23:53 1 · 回答

NO.PZ2019010402000021 0.8533 1.0432 B is correct. 考点二叉树求value 解析 πu=1+Rf−−1+5%−0.921.12−0.92=0.65\pi\text{u}=\frac{1+R_f-{u-=\frac{1+5\%-0.92}{1.12-0.92}=0.65πu=u−+Rf​−=1.12−0.921+5%−0.92​=0.65 画二叉树 这一题是美式期权,在t=1时执行,put的价值更高(=32-29.44=2.56),所以投资者会选择提前执行。此时 P0=2.56×0.35+0×0.651.05=0.8533P_0=\frac{2.56\times0.35+0\times0.65}{1.05}=0.8533P0​=1.052.56×0.35+0×0.65​=0.8533请问1.6384和0.5461是什么

2021-11-04 07:11 1 · 回答

为什么这道题就不考虑假设t=1时刻行权情况下,s+情况下p的时间价值?

2019-03-09 22:49 3 · 回答