momo · 2023年08月11日
NO.PZ2023061301000005
问题如下：
Compared with bootstrap resampling, jackknife resampling:
选项：
A.
is done with replacement.
B.
usually requires that the number of repetitions is equal to the sample size.
C.
produces dissimilar results for every run because resamples are randomly
drawn.
解释：
B is correct. For a sample of size n, jackknife resampling usually requires n repetitions.
In contrast, with bootstrap resampling, we are left to determine how many
repetitions are appropriate.
c为什么不对。。。。
NO.PZ2023061301000005 问题如下 Comparewith bootstrresampling, jackknife resampling: A.is ne with replacement. B.usually requires ththe number of repetitions is equto the sample size. C.proces ssimilresults for every run because resamples are ranmlyawn. B is correct. For a sample of size n, jackknife resampling usually requires n repetitions.In contrast, with bootstrresampling, we are left to termine how manyrepetitions are appropriate. 题目Otema Chi ha spreaheet with 108 monthly returns for shares in Marunou Corporation. He writes a software progrthuses bootstrresampling to create 200 resamples of this Marunou ta sampling with replacement. Earesample h108 ta points. Chi's progrcalculates the meof eaof the 200 resamples, anthen it calculates ththe meof these 200 resample means is 0.0261. The progrsubtracts 0.0261 from eaof the 200 resample means, squares eaof these 200 fferences, anas the squarefferences together. The result is 0.835. The progrthen calculates estimate of the stanrerror of the sample mean.The estimatestanrerror of the sample meis closest to:为什么0.835代表下面的公式这个又代表什么呢
NO.PZ2023061301000005问题如下 Comparewith bootstrresampling, jackknife resampling: A.is ne with replacement.B.usually requires ththe number of repetitions is equto the sample size.C.proces ssimilresults for every run because resamples are ranmlyawn. B is correct. For a sample of size n, jackknife resampling usually requires n repetitions.In contrast, with bootstrresampling, we are left to termine how manyrepetitions are appropriate. 没有看懂。。。。。，
