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台风来了 · 2023年08月02日

关于BP检验和条件异方差

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问题如下:

You are a junior analyst at an asset management firm. Your supervisor asks you to analyze the return drivers for one of the firm’s portfolios.

Model 3: RETi = b0 + bMRKTMRKTi + bHMLHMLi + bVIXVIXi + bSMBSMBi + bMOMMOMi + εi.

Your supervisor is concerned about conditional heteroskedasticity in Model 3 and asks you to perform the Breusch–Pagan (BP) test. At a 5% confidence level, the BP critical value is 11.07. You run the regression for the BP test; the results are shown in Exhibit 1.


Calculate the BP test statistic using the data in Exhibit 1 and determine whether there is evidence of heteroskedasticity.

选项:

A.

1.264, so there is no evidence of heteroskedasticity

B.

6.251, so there is no evidence of heteroskedasticity

C.

81.792, so there is evidence of heteroskedasticity

解释:

B is correct. The BP test statistic is calculated as nR2, where n is the number of observations and R2 is from the regression for the BP test. So, the BP test statistic= 96 × 0.06511 = 6.251. This is less than the critical value of 11.07, so we cannot reject the null hypothesis of no heteroskedasticity. Thus, there is no evidence of heteroskedasticity.

老师,您好!


The BP test statistic is calculated as nR2, 有哪个地方讲到过BP检验的统计量如何计算、检验的原假设如何定义,以及什么条件下拒绝原假设的内容啊?麻烦老师再补充一下吧,谢谢了!

1 个答案

星星_品职助教 · 2023年08月04日

同学你好,

本提问涉及到整个知识点的讲解。可以参考基础班的如下部分:

对应讲义及结论如下:

如对于课上讲解内容仍有疑问,可以就疑问处后续提问。