开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)｜3.2.5(安卓)APP下载

返回

六姑娘 · 2023年07月08日

这个显著性水平为何不除以2

  1. Quantitative

NO.PZ2022123001000107

问题如下：

Consider a two-tailed test of the hypothesis that the population mean is zero. The sample has 50 observations. The population is normally distributed with a known variance.


At a 0.05 significance level, the rejection points are most likely at:

选项：

A.–2.010 and 2.010 B.–2.009 and 2.009 C.–1.960 and 1.960

解释：

The appropriate test statistic is a z-statistic because the sample comes from a normal distributed population with known variance. A z-test does not use degrees of freedom. This test is two-sided at the 0.05 significance level, and the rejection point conditions are z > 1.960 and z < –1.960.

这个显著性水平为何不除以2



添加评论
1 个答案

星星_品职助教 · 2023年07月09日

同学你好，

这道题表格中的z-distribution部分中，给出的都是α的值。由于significance level就是α自身，不是α/2。所以根据题干中给出At a 0.05 significance level，只能去表格中找α=0.05，不能找0.025。

然后对应出1.96即可。



  • 1

    回答

  • 0

    关注

  • 387

    浏览
相关问题

NO.PZ2022123001000107 问题如下 Consir a two-tailetest of the hypothesis ththepopulation meis zero. The sample h50 observations. The population isnormally stributewith a known variance. a 0.05 significanlevel, the rejection points are most likely at: A.–2.010 an2.010 B.–2.009 an2.009 C.–1.960 an1.960 The appropriate test statistic is a z-statisticbecause the sample comes from a normstributepopulation with knownvariance. A z-test es not use grees of freem. This test is two-siatthe 0.05 significanlevel, anthe rejection point contions are z 1.960 anz –1.960. =50-1=49，two taile a/2然后得出答案A，错在哪里了呢？

2024-09-04 11:56 1 · 回答

NO.PZ2022123001000107 问题如下 Consir a two-tailetest of the hypothesis ththepopulation meis zero. The sample h50 observations. The population isnormally stributewith a known variance. a 0.05 significanlevel, the rejection points are most likely at: A.–2.010 an2.010 B.–2.009 an2.009 C.–1.960 an1.960 The appropriate test statistic is a z-statisticbecause the sample comes from a normstributepopulation with knownvariance. A z-test es not use grees of freem. This test is two-siatthe 0.05 significanlevel, anthe rejection point contions are z 1.960 anz –1.960. 这个题目表格出法很奇怪不同于正常的表格，考试会这样给吗？那t 表格也是这种给法吗？

2024-07-18 18:23 1 · 回答

NO.PZ2022123001000107 问题如下 Consir a two-tailetest of the hypothesis ththepopulation meis zero. The sample h50 observations. The population isnormally stributewith a known variance. a 0.05 significanlevel, the rejection points are most likely at: A.–2.010 an2.010 B.–2.009 an2.009 C.–1.960 an1.960 The appropriate test statistic is a z-statisticbecause the sample comes from a normstributepopulation with knownvariance. A z-test es not use grees of freem. This test is two-siatthe 0.05 significanlevel, anthe rejection point contions are z 1.960 anz –1.960. 答案This test is two-sithe 0.05 significanlevel, anthe rejection point contions are z 1.960 anz –1.960.为什么reject部分不是z 1.960 anz –1.960? 我记得讲课视频是这样啊

2024-02-01 23:33 1 · 回答