开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)｜3.2.5(安卓)APP下载

返回

小熊猫 · 2023年06月09日

小数点保留几位？

  1. FRM I
  2. Quantitative

NO.PZ2020010301000017

问题如下：

Based on the probabilities in the diagram below, considering the three distinct pairs of events, how many of these pairs are independent?





选项：

A.

0

B.

1

C.

2

D.

3

解释：

We can use the rule that events are independent if their joint probability is the product of the probability of each. Pr(A) = 48%, Pr(B) = 55%, Pr(C) = 53%, Pr(A∩B) = 21% ≠ (48% * 55%), Pr(A∩C) = 25% ≠ (48% * 53%), Pr(B∩C) = 28% ≠ (55% * 53%). None of these events are pairwise independent.

Pr(A∩C) = 25% ≠ (48% * 53%)？不等于么？48%*53%不是25.44%？题里都没有小数出现，这不能算是25%吗？

添加评论
1 个答案

pzqa27 · 2023年06月09日

嗨，爱思考的PZer你好：


严格来说不行，因为25%并不等于25.44%，所以 A和C不是独立事件

----------------------------------------------
就算太阳没有迎着我们而来，我们正在朝着它而去，加油！

  • 1

    回答

  • 0

    关注

  • 262

    浏览
相关问题

NO.PZ2020010301000017 问题如下 Baseon the probabilities in the agrbelow, consiring the three stinpairs of events, how many of these pairs are inpennt? A.0 B.1 C.2 3 We cuse the rule thevents are inpennt if their joint probability is the proof the probability of each. Pr(= 48%, Pr(= 55%, Pr(= 53%, Pr(A∩= 21% ≠ (48% * 55%), Pr(A∩= 25% ≠ (48% * 53%), Pr(B∩= 28% ≠ (55% * 53%). None of these events are pairwise inpennt. 这道题可以通过看图、不计算就知道答案吗？

2024-01-28 17:07 1 · 回答

NO.PZ2020010301000017 问题如下 Baseon the probabilities in the agrbelow, consiring the three stinpairs of events, how many of these pairs are inpennt? A.0 B.1 C.2 3 We cuse the rule thevents are inpennt if their joint probability is the proof the probability of each. Pr(= 48%, Pr(= 55%, Pr(= 53%, Pr(A∩= 21% ≠ (48% * 55%), Pr(A∩= 25% ≠ (48% * 53%), Pr(B∩= 28% ≠ (55% * 53%). None of these events are pairwise inpennt. P(AB)和P(A∩B)有区别么

2023-09-16 17:00 1 · 回答

这道题是什么意思？

2020-02-03 20:47 1 · 回答