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Lance · 2023年04月27日

the population standard deviation

  1. CFA I
  2. Quantitative

NO.PZ2018062016000132

问题如下：

Claire believes that the mean price of the commercial residential building is greater than $155,000. The population standard deviation is $25,000. A random sample of 36 commercial residential buildings in the area has a mean price of $159,750. Claire conduct the hypothesis test at a 1% level of significance. The value of the calculated test statistic is closet to:

选项：

A.

1.14.

B.

0.19.

C.

1.33.

解释：

A is correct. This is a one-tailed hypothesis since the alternative hypothesis only allows values greater than the hypothesized value. z=159750-155000/(25000/6)=1.14

这个25000不是总体样本方差嘛？

population不是总体方差嘛？请老师解惑下。

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星星_品职助教 · 2023年04月27日

同学你好，

1）“ The population standard deviation is $25,000”指的是总体标准差σ=25,000

2）z统计量的计算公式中，分母为标准误，standard error=σ/√n ，即25000/√36

Lance · 2023年04月29日

谢谢老师 总体用希腊字母，样本用英文字母

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NO.PZ2018062016000132 问题如下 Claire believes ththe mepriof the commerciresintibuilng is greater th$155,000. The population stanrviation is $25,000. A ranm sample of 36 commerciresintibuilngs in the area ha mepriof $159,750. Claire conthe hypothesis test a 1% level of significance. The value of the calculatetest statistic is closet to: A.1.14. B.0.19. C.1.33. A is correct. This is a one-tailehypothesis sinthe alternative hypothesis only allows values greater ththe hypothesizevalue. z=159750-155000/(25000/6)=1.14 这个知识点对应哪一章节

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NO.PZ2018062016000132 0.19. 1.33. A is correct. This is a one-tailehypothesis sinthe alternative hypothesis only allows values greater ththe hypothesizevalue. z=159750-155000/(25000/6)=1.1425000/6这步，6是哪个条件出来的？

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NO.PZ2018062016000132 0.19. 1.33. A is correct. This is a one-tailehypothesis sinthe alternative hypothesis only allows values greater ththe hypothesizevalue. z=159750-155000/(25000/6)=1.14求单尾假设significant level是1%还是0.5%

2021-11-09 12:09 1 · 回答

NO.PZ2018062016000132 我用上方公式算对了这题。但我不明白分子为什么不可以是the hypothesizevalue减去X̄？ 如果是要衡量the hypothesizevalue在分布上离均值X̄多远，既然分布是左右对称，【the hypothesizevalue减去X̄再除以标准误】和【X̄减去the hypothesizevalue再除以标准误】，算出来的数值只是相差了一个正负号。我该怎么理解公式的分子【X̄减去the hypothesizevalue】的意思？

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