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Potatowpn · 2023年03月16日

请问UL的公式中P*(1-P)在是在那个知识点中出现的?强化课中老师提到的是LGD的平方,这两个是一样的么?

NO.PZ2020033002000004

问题如下:

A bank granted Client A a total credit facility of $500,000, of which 70% is currently outstanding. The client's probability of default for the following year is estimated to be 2%, the loss given default is 50%, and the standard deviation of loss given default is 30%. The undrawn portion at the time of default assumes a 50% withdrawal. What is the bank's best estimate of expected and unexpected losses (standard deviation) ?

选项:

A.

EL = $3500, UL = $55,229

B.

EL = $3500, UL = $28,649

C.

EL = $4250, UL = $67,064

D.

EL = $4250, UL = $34,788

解释:

D is correct.

考点:Risk Contribution

解析:

AE=70%x$500,000+50%*30%*$500,000=$425,000

EL=425,000*2%*50%=4250

UL的公式如下:

UL=AEp×σLGD2+p×(1p)×LGD2UL=AE\ast\sqrt{p\times\sigma_{LGD}^2+p\times{(1-p)}\times{LGD}^2}

代入公式,有

UL=34,788



1 个答案

品职答疑小助手雍 · 2023年03月16日

同学你好,LGD的平方是后面的那一项,红框这一项是PD的方差。

要么违约要么不违约,PD是服从二项分布的,一级里讲过,二项分布的方差就是p*(1-p)

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