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小蜜蜂jj1 · 2023年02月06日

老师为什么这里不用6C2乘以0.1乘以0.1呢?

NO.PZ2017092702000091

问题如下:

The cumulative distribution function for a discrete random variable is shown in the following table.

The probability that X will take on a value of either 2 or 4 is closest to:

选项:

A.

0.20.

B.

0.35.

C.

0.85.

解释:

A is correct.

The probability that X will take on a value of 4 or less is: F(4) = P(X ≤ 4) = p(1) + p(2) + p(3) + p(4) = 0.60. The probability that X will take on a value of 3 or less is: F(3) = P(X ≤ 3) = p(1) + p(2) + p(3) = 0.50. So, the probability that X will take on a value of 4 is: F(4) – F(3) = p(4) = 0.10. The probability of X = 2 can be found using the same logic: F(2) – F(1) = p(2) = 0.25 – 0.15 = 0.10. The probability of X taking on a value of 2 or 4 is: p(2) + p(4) = 0.10 + 0.10 = 0.20.

如题。。。。。。。。

1 个答案

星星_品职助教 · 2023年02月07日

同学你好,

1)6C2代表在6个中以无排序的方式任意选择2个。本题已经限定了要计算的就是p(2) 和p(4) ,不是任意选择,不能使用组合的方法。

2)本题使用的公式为当A、B为互斥事件时,P(AB)=0,则P(A+B)=P(A)+P(B)。算出p(2) 和 p(4) 各自的概率后直接相加即可。


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