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zzzz不歪 · 2023年02月04日

题目中提到的6.3%有什么用

NO.PZ2021062201000004

问题如下:

Lena Hunziger has designed the three-asset portfolio summarized below:


Hunziger estimated the portfolio return to be 6.3%. What is the portfolio standard deviation?

选项:

A.

13.07%

B.

13.88%

C.

14.62%

解释:

C is correct. For a three-asset portfolio, the portfolio variance is:

σ2Rp=w12σ2(R1)+w22σ2(R2)+w32σ2(R3)+2w1w2Cov(R1,R2)+2w1w3Cov(R1,R3)+2w2w3Cov(R2,R3){\sigma ^2}{R_p} = w_1^2{\sigma ^2}({R_1}) + w_2^2{\sigma ^2}({R_2}) + w_3^2{\sigma ^2}({R_3}) + 2{w_1}{w_2}Cov({R_1},{R_2}) + 2{w_1}{w_3}Cov({R_1},{R_3}) + 2{w_2}{w_3}Cov({R_2},{R_3})

=(0.20)2(196) + (0.30)2(225) + (0.50)2(400) + 2(0.20)(0.30)(105) + (2)(0.20)(0.50)(140) + (2)(0.30)(0.50)(150)

=7.84 + 20.25 + 100 + 12.6+ 28 +45

=213.69

知识点:Probability Concepts

6.3%在计算中是不是没用到

1 个答案

星星_品职助教 · 2023年02月04日

同学你好, 没用到,这个条件在本题里没用。

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NO.PZ2021062201000004 问题如下 Lena Hunziger hsignethe three-asset portfolio summarizebelowHunziger estimatethe portfolio return to 6.3%. Whis the portfolio stanrviation? A.13.07% B.13.88% C.14.62% C is correct. For a three-asset portfolio, the portfolio varianisσ2Rp=w12σ2(R1)+w22σ2(R2)+w32σ2(R3)+2w1w2Cov(R1,R2)+2w1w3Cov(R1,R3)+2w2w3Cov(R2,R3){\sigma ^2}{R_p} = w_1^2{\sigma ^2}({R_1}) + w_2^2{\sigma ^2}({R_2}) + w_3^2{\sigma ^2}({R_3}) + 2{w_1}{w_2}Cov({R_1},{R_2}) + 2{w_1}{w_3}Cov({R_1},{R_3}) + 2{w_2}{w_3}Cov({R_2},{R_3})σ2Rp​=w12​σ2(R1​)+w22​σ2(R2​)+w32​σ2(R3​)+2w1​w2​Cov(R1​,R2​)+2w1​w3​Cov(R1​,R3​)+2w2​w3​Cov(R2​,R3​)=(0.20)2(196) + (0.30)2(225) + (0.50)2(400) + 2(0.20)(0.30)(105) + (2)(0.20)(0.50)(140) + (2)(0.30)(0.50)(150)=7.84 + 20.25 + 100 + 12.6+ 28 +45 =213.69 知识点Probability Concepts 所以variance-covarianmatrix的意思就是两两协方差/方差的值吗

2023-05-09 01:06 1 · 回答

NO.PZ2021062201000004 问题如下 Lena Hunziger hsignethe three-asset portfolio summarizebelowHunziger estimatethe portfolio return to 6.3%. Whis the portfolio stanrviation? A.13.07% B.13.88% C.14.62% C is correct. For a three-asset portfolio, the portfolio varianisσ2Rp=w12σ2(R1)+w22σ2(R2)+w32σ2(R3)+2w1w2Cov(R1,R2)+2w1w3Cov(R1,R3)+2w2w3Cov(R2,R3){\sigma ^2}{R_p} = w_1^2{\sigma ^2}({R_1}) + w_2^2{\sigma ^2}({R_2}) + w_3^2{\sigma ^2}({R_3}) + 2{w_1}{w_2}Cov({R_1},{R_2}) + 2{w_1}{w_3}Cov({R_1},{R_3}) + 2{w_2}{w_3}Cov({R_2},{R_3})σ2Rp​=w12​σ2(R1​)+w22​σ2(R2​)+w32​σ2(R3​)+2w1​w2​Cov(R1​,R2​)+2w1​w3​Cov(R1​,R3​)+2w2​w3​Cov(R2​,R3​)=(0.20)2(196) + (0.30)2(225) + (0.50)2(400) + 2(0.20)(0.30)(105) + (2)(0.20)(0.50)(140) + (2)(0.30)(0.50)(150)=7.84 + 20.25 + 100 + 12.6+ 28 +45 =213.69 知识点Probability Concepts 我好像沒有學過這條公式的感覺

2023-03-04 05:11 1 · 回答

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2022-12-20 20:21 1 · 回答

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2022-10-02 18:45 1 · 回答