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NO.PZ202106160100000103问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0.B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式，ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到，MXN/GBP换成GBP/MXN后，因为标价货币和基础货币的地位对调了，所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到，aler A对于MXN报价便宜一些，那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN，然后去aler B处卖掉MXN，但是在aler B卖掉MXN就要用aler B的买价，0.0403。可以直观看到投资者以0.0404价格买入，却以0.0403价格卖出，是没有利润可得的。所以投资者不会去做这笔三角套汇，那么三角套汇的利润自然为0。 比如24.774214原为A的bi但取倒数后是否为ask的价格？如是，可否讲解下原理？不太理解

NO.PZ202106160100000103 问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0. B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式，ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到，MXN/GBP换成GBP/MXN后，因为标价货币和基础货币的地位对调了，所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到，aler A对于MXN报价便宜一些，那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN，然后去aler B处卖掉MXN，但是在aler B卖掉MXN就要用aler B的买价，0.0403。可以直观看到投资者以0.0404价格买入，却以0.0403价格卖出，是没有利润可得的。所以投资者不会去做这笔三角套汇，那么三角套汇的利润自然为0。 转换后alerA的报价是GBP/MXN 0.0403-0.0404，我是用这里的biprice0.0403和aler B的biprice0.0403对比，然后得到结果是0，这样做有没有问题？

NO.PZ202106160100000103 问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0. B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式，ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到，MXN/GBP换成GBP/MXN后，因为标价货币和基础货币的地位对调了，所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到，aler A对于MXN报价便宜一些，那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN，然后去aler B处卖掉MXN，但是在aler B卖掉MXN就要用aler B的买价，0.0403。可以直观看到投资者以0.0404价格买入，却以0.0403价格卖出，是没有利润可得的。所以投资者不会去做这笔三角套汇，那么三角套汇的利润自然为0。 老师，我算出来MXN/GBP是24.7742-24.8069，当转化成GBP/MXN以后，算出来的数据，为什么要把biask的位置也调换呢？ 另外按照这个逻辑，算出来alerA 是0.04031-0.04036，alerB 是0.0403-0.0404，这个无法判断说谁便宜吧？怎么判断从哪里买入比较划算呢？

NO.PZ202106160100000103 问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0. B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式，ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到，MXN/GBP换成GBP/MXN后，因为标价货币和基础货币的地位对调了，所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到，aler A对于MXN报价便宜一些，那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN，然后去aler B处卖掉MXN，但是在aler B卖掉MXN就要用aler B的买价，0.0403。可以直观看到投资者以0.0404价格买入，却以0.0403价格卖出，是没有利润可得的。所以投资者不会去做这笔三角套汇，那么三角套汇的利润自然为0。 我怎么理解的是要卖出EUR，买入GBP。是要乘以较小的那个数就是（0.9467+14/10000）这个数。难道是我理解错了，有点(+﹏+)~晕了，不知道啥时候用乘法和除法以前的题目都做对了，但是这里怎么错了。