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Benny™ · 2022年11月03日

不理解

NO.PZ2017092702000095

问题如下:

A call option on a stock index is valued using a three-step binomial tree with an up move that equals 1.05 and a down move that equals 0.95. The current level of the index is $190, and the option exercise price is $200. If the option value is positive when the stock price exceeds the exercise price at expiration and $0 otherwise, the number of terminal nodes with a positive payoff is:

选项:

A.

one.

B.

two.

C.

three.

解释:

A is correct.

Only the top node value of $219.9488 exceeds $200

来到第二次上涨的时候不是已经超过200了吗?这是向positive方向折了两次的意思吧?上课好像没详细讲到这东西怎么玩的,可以介绍一下吗



2 个答案

星星_品职助教 · 2022年11月04日

@Benny™

是的,terminal是最终一期的意思,本题里就是最终第三期二叉树的四个值。

星星_品职助教 · 2022年11月03日

同学你好,

这种题型的应用和option的性质会在衍生品科目中具体学习。数量中了解基本原理即可。

“an up move that equals 1.05 and a down move that equals 0.95”指得是价格上涨和下降的倍数。例如首期190元,下一期上涨后的价格为190*1.05=199.5;下降的价格为190*0.95=180.5元。这两个价格构成了下一期二叉树的两个节点。

同理,199.5这个价格下一期会变为199.5*1.05=209.4750(上涨),即“向positive方向折了两次的意思”

下降价格变为199.5*0.95=189.5250,以此类推,可以得到二叉树上所有的节点价格。

由于本题问的是“the number of terminal nodes with a positive payoff”,所以只需要考虑最后一期(terminal)的价格即可,按照上面的原理计算出最后一期的四个价格,发现只有一个超过了200,所以有positive payoff的就是one。



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