ruby5ltc · 2022年06月29日
NO.PZ2021071601000008
问题如下：
John, an analyst ran a
simple regression explaining the variation in electricity consumption as a
function of temperature. The total variation of the dependent variable
was 132.08, and the explained variation was 60.38. She had 60 monthly
observations.
Calculate the coefficient of determination.
选项：
A.0.4571 B.2.19 C.0.21解释：
The coefficient of determination is 0.4571:
R²=SSR/SST,怎么看出来题干给的条件描述的就是SSR和SST?
NO.PZ2021071601000008 问题如下 John, analyst ra simple regression explaining the variation in electricity consumption a function of temperature. The totvariation of the pennt variable w132.08, anthe explainevariation w60.38. She h60 monthly observations. Calculate the coefficient of termination. A.0.4571 B.2.19 C.0.21 The coefficient of termination is 0.4571:ExplainvariationTotalvariation=60.38132.08=0.4571\frac{{{\rm{Explain variation}}}}{{{\rm{Totvariation}}}} = \frac{{60.38}}{{132.08}} = 0.4571TotalvariationExplainvariation=132.0860.38=0.4571 到底是 ssr sst还是rss tss 啊 我看视频里说的是ssr sst 但是框架图里写的是 rss tss
NO.PZ2021071601000008 问题如下 John, analyst ra simple regression explaining the variation in electricity consumption a function of temperature. The totvariation of the pennt variable w132.08, anthe explainevariation w60.38. She h60 monthly observations. Calculate the coefficient of termination. A.0.4571 B.2.19 C.0.21 The coefficient of termination is 0.4571:ExplainvariationTotalvariation=60.38132.08=0.4571\frac{{{\rm{Explain variation}}}}{{{\rm{Totvariation}}}} = \frac{{60.38}}{{132.08}} = 0.4571TotalvariationExplainvariation=132.0860.38=0.4571 样本方差的分母应为59，总体方差的分母是60，故最后SSR/SST是否应为60.38/132.08再乘以59/60。
NO.PZ2021071601000008请问老师，这个表达在视频哪里，我并没有第一反应出explainevariation 在这里就是SSR
