NO.PZ2015120604000060
问题如下:
According to the above table, what is the expected return of X?
选项:
A.
1.
B.
1.6.
C.
-3.2.
解释:
A is correct
Expected return of X= (0.2)(-2) + (0.6)(1) + (0.2)(4) = 1
老师可以讲解一下expect return 的含义吗?这题考查的方法感觉不太理解
NO.PZ2015120604000060 问题如下 Accorng to the above table, whis the expectereturn of X? A.1. B.1.6. C.-3.2. A is correctExpectereturn of X= (0.2)(-2) + (0.6)(1) + (0.2)(4) = 1
NO.PZ2015120604000060 问题如下 Accorng to the above table, whis the expectereturn of X? A.1. B.1.6. C.-3.2. A is correctExpectereturn of X= (0.2)(-2) + (0.6)(1) + (0.2)(4) = 1 老师,以第一格数据为例,0.2是joint probability,那就应该是P(XY)的概率,但为什么在计算的时候就直接把它当作P(X)的概率了呢?
NO.PZ2015120604000060 Joint Probability,是不是应该P(XY),那么不应该是X=-2,Y=5,同时发生的概率是0.2。为什么在计算的时候直接-2✖️0.2,0.2里面不会包含Y=5发生的概率吗。
如果x=-2, y=2 时的概率不等于0,要怎么解题?